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amm1812
3 years ago
7

Brainliest..... plz help!!!!!!!!!

Physics
1 answer:
alisha [4.7K]3 years ago
4 0
Tamam hocam nasılsınız hocam proje konularını atabilirmisiniz ne kadar çok seviyorum çok öpüyorum iyi akşamlar yarın görüşürüz iyi geceler Allah rahatlık var bir şey var ya bir insan değilim ki bir şey olmaz sen kaç gibi müsait olur musun lütfen bana yardımcı olabilir misin bir insan bir
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I have about 4 questions can anyone help? Its about motion (I don't quite know what type of science that is...)
Neko [114]
Motion is physics. motion is the displacement,distance,velocity, acceleration, time, and speed.
6 0
3 years ago
A Van de Graaff generator causes a total charge q to build up on a metal sphere of radius r. Which variable does not affect the
Maru [420]

Answer:

The radius r of the metal sphere.

Explanation:

From Gauss's law we know that for a spherical charge distribution with charge Q, the electrical field at distance R from the center of the sphere is given by

E=\frac{Q}{4\pi \epsilon_oR^2}

What is important to notice here is that the radius of the sphere does not matter because any test charge sitting at distance R feels the force as if all the charge Q were sitting at the center of the sphere.

This situation is analogous to the gravitational field. When calculating gravitational force due to a body like the sun or the earth, we take not of only the mass of the sun and the distance from it's center; the sun's radius does not matter because we assume all of its mass to be concentrated at the center.

6 0
3 years ago
Which is a physical property that can be used to tell one substance from another?
siniylev [52]

Should be B. Density.

3 0
3 years ago
Read 2 more answers
A dumped harmonic oscillator of a mass of 500 g has a period of 0.5 second. The amplitude of the oscillation is decreasing 2.0 %
inn [45]

Answer:

The answer is below

Explanation:

The amplitude decreases by 2%  during each oscillation. Hence the decrease in amplitude can be represented by an exponential decay in the form:

y = abˣ; where x ad y are variables, a is the initial value and b is the factor.

Let y represent the amplitude after x oscillations. Since the initial amplitude is 10 cm, hence:

a = 10 cm, b = 2% = 0.02.

Therefore:

y = 10(0.02)ˣ

The amplitude after 25 oscillations is gotten by substituting x = 25 into the equation. Hence:

y = 10(0.02)²⁵

y= 3.355 * 10⁻⁴² cm

The amplitude after 25 oscillations is 3.355 * 10⁻⁴² cm

7 0
3 years ago
A weather balloon is partially inflated with helium gas to a volume of 2.0 m³. The pressure was measured at 101 kPa and the temp
Yanka [14]

Answer:

4.7 m³

Explanation:

We'll use the gas law P1 • V1 / T1 = P2 • V2 / T2

* Givens :

P1 = 101 kPa , V1 = 2 m³ , T1 = 300.15 K , P2 = 40 kPa , T2 = 283.15 K

( We must always convert the temperature unit to Kelvin "K")

* What we want to find :

V2 = ?

* Solution :

101 × 2 / 300.15 = 40 × V2 / 283.15

V2 × 40 / 283.15 ≈ 0.67

V2 = 0.67 × 283.15 / 40

V2 ≈ 4.7 m³

7 0
2 years ago
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