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Zolol [24]
3 years ago
11

I have about 4 questions can anyone help? Its about motion (I don't quite know what type of science that is...)

Physics
1 answer:
Neko [114]3 years ago
6 0
Motion is physics. motion is the displacement,distance,velocity, acceleration, time, and speed.
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A distant star gives off a visible range of light whose color depends on its temperature. Which model of light does this example
aleksklad [387]

The statement 'a distant star gives off a visible range of light whose color depends on its temperature' is supported by the wave model​.

<h3>What is wavelength?</h3>

The wavelength can be defined as the periodic distance of a given wave that repeats in a constant way.

The emissivity of particles is a function of both wavelength and temperature of a given material/object. Visible wavelengths range from 700 nm to 400 nm (violet color).

Star temperature largely determines its color, blue stars are warmer than yellow and red stars, and red stars are cooler than yellow stars.

Learn more about visible wavelengths here:

brainly.com/question/10728818

4 0
3 years ago
The drawing (not to scale) shows one alignment of the sun, earth, and moon. the gravitational force vector f sm that the sun exe
ad-work [718]

Solution:

Ms = 1.99 × 1030 kg− mass of Sun;

Me = 5.98 × 1024kg− mass of Earth;

Mm = 7.35 × 1022kg − mass of Moon;

rSM = 1.50 × 1011m − distance to the Moon from the Sun;

rEM = 3.85 × 108m − distance to the Moon from the Earth;

 

The gravitational force that acts on the Moon by the Earth (Law of Gravity):

 

F_{e} = G \frac {M_{e} * M_{m} } {r^{2}_{EM}} = 6.67 x&#10;10^{-11} N * (\frac {m} {kg})^{2}*\frac {5.98 * 10^{24} kg * 7.35 * 10^{22} kg}&#10;{(3.85 x 10^{8}m)^{2}} = 1.98 * 10^{20} N

The gravitational force that acts on the Moon by the Sun (Law of Gravity):

F_{S} = G \frac {M_{s} * M_{m} } {r^{2}_{EM}} = 6.67 x&#10;10^{-11} N * (\frac {m} {kg})^{2}*\frac {1.99 * 10^{30} kg * 7.35 * 10^{22} kg}&#10;{(1.50 x 10^{11}m)^{2}} = 4.34 * 10^{20} N

Net gravitational force on the moon:

F = F_{e} + F_{s}

Pythagorean theorem for a right triangle ABC:

 

F = \sqrt {F^{2}_{S} + F^{2}_{e}} = \sqrt {(1.98 *&#10;10^{20}N)^{2} + (4.34 * 10^{20} N)^{2}} = 4.77 * 10^{20}N

Answer: Answer: magnitude of the net gravitational force on the moon is 4.77 × 10^{20}N.

4 0
3 years ago
A torque of 12 N*m is applied to a solid uniform disk of radius 0.50 m. If the disk accelerates at 2.6 rad/s^2 what is the mass
VladimirAG [237]

Answer:

mass = 36.92 kg

Explanation:

We have given the torque \tau =12 N-m

Radius of the disk r = 0.50 m

Angular acceleration \alpha =2.6rad/sec^2

We know that torque is given by \tau =I\alpha here I is moment of inertia and \alpha is angular acceleration

So 12=I\times 2.6

I=\frac{12}{2.6}=4.6153kgm^2

Moment of inertia is given by I=\frac{1}{2}mr^2

4.6153=\frac{1}{2}m0.5^2

m = 36.92 kg

The given answer is not matched with this answer but after calculation i got m =36.92 kg

4 0
4 years ago
Two beams of coherent light travel different paths, arriving at point P. If the destructive interference is to occur at point P,
swat32

Answer:

Explanation:

When two coherent light beams travel different paths and arrive at a point , there will be difference in the length of path travelled by them . If this difference is zero then both will reinforce each other and their brightness will add up . Hence there will be constructive interference .

If their path difference is not zero but it is equal to odd multiple of their half wavelength like λ / 2 , 3 λ / 2 , 5 λ /2 , 7 λ /2 etc , then instead of reinforcing each other , they will destroy each other . This is called destructive interference . As a result of it , darkness will prevail at the point where they meet or interfere.

6 0
3 years ago
A 4.2-g bullet is fired at a speed of 370 m/s into a stationary lead block, which moves a distance of 1.2 m before coming to res
Natali5045456 [20]

Answer:

(a) F = 239.575 N (b) t = 0.00649s or 6.49 ms

Explanation:

(a) By law of energy conservation, the bullet kinetic energy will be transferred to work done on stopping it from moving.

Formula for Kinetic Energy E_k = \frac{mv^2}{2} where m is bullet mass, v is the velocity

Formula for work W = FS where F is the average force and S is the distance travelled.

E_k = W

\frac{mv^2}{2} = FS

F = \frac{mv^2}{2S}

Substitute m = 4.2 g = 0.0042 kg, v = 370 m/s and S = 1.2 (m)

F = \frac{0.0042*370^2}{2*1.2} = 239.575 N

(b) If the force is constant, since the mass is constant and F = ma according to Newton's 2nd law, the acceleration on bullet is also constant

a = \frac{F}{m} = \frac{239.575}{0.0042} = 57041.67 (m/s^2)

We also have v(t) = v_0 + at

At the time the bullet is coming to rest, v(t) = 0, a = -57041.67 m/s^2

Therefore, 0 = 370 - 57041.67t

t = \frac{370}{57041.67} = 0.00649 s = 6.49 ms

3 0
4 years ago
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