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Shkiper50 [21]
3 years ago
9

a 5 kg block is pulled across a table by a horizontal force of 40 n with a frictional force 8 n opposing the motion. calculate t

he acceleration of the object
Physics
2 answers:
MAXImum [283]3 years ago
7 0
By Newton's 2nd law, m*a=sum_of_forces where m is the mass and a the acceleration. Here there are two forces in opposed directions.

Thus 5*a=40-8=32 therefore a=32/5=6.4m^s/2
arlik [135]3 years ago
5 0

Answer:

a=6.4m/s^2

Explanation:

from basic terms , this problem can be tied to newtons second law of motion,

which states that

The rate of change in motion is directly proportional to the force applied .

a force is that which tends to change a body's state of rest or uniform motion in a straight line.

frictional force is the force tat oppose the motion between an object

acceleration is the cane in velocity per time

mass is the composition of matter in an object.

f\alpha m(v-u)/t

f=km(v-u)/t

k=1

f=m(v-u)/t

(v-u)/t=a

f=ma

the sum of forces on this block will be

F-Fr=ma

notice that the frictional force is in opposition to the horizontal force, hence it is designated as a negative force

40-8=5a

32=5a

a=32/5

a=6.4m/s^2

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<h3>What is the centripetal force?</h3>

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CQ

Flag

a merry go round with a radius of R=1.8 m and moment of inertia I=184 kg-m^2 is spinning with an initial angular speed of w=1.48 rad/s in the counter clockwise direction when viewed from above a person with mass m=76 kg and velocity v=4.7 m/s runs on a path tangent to the merry go round once at the merry go round the person jumps on and holds on to the rim of the merry go round angular speed of the merry go round after the person jumps on 2.127 rad/s Once the merry go round travels at this new angular speed with what force does the person need to hold on?

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