About 7.5 miles if you divide 45/3 is 15 so divide 15/2 which is 7.5
I am pretty sure your answer will be 96783564.8, but it may need to be rounded. If I am wrong, I am sorry.
Hope this helps~!
To solve by elimination you need to solve for each variable, in this case x, y, and z
x = 1/3
y = 7/3
z = 0
Answer: 1.
Yes , the data franchise owner is collecting, will be helpful in order to counter the criticism from the critic. As he has a record for every delivery they are making on daily basis.
2.
The scenario is that for every fifth customer , the owner cross the four lines he makes. Thus a pack of five and easy to remember. As the data on regular week days is less, As can do the same for the third customer. Crossing the 2 lines for 3rd customer.
3.
With this provision of crossing the third customer, the owner can have a better check on the late delivery. As it will bring in his notice earlier as compared to fifth crossing.
4.
With the data as provided in the table, we can come to the conclusion that on weekends , i.e. both on time delivery and late deliveries are high in numbers. It must be because of high demand on that days. So owner must make some provision like hiring some more delivery boys for weekend in order to reduce the late deliveries.
Step-by-step explanation:
Three consecutive integers are x, x+1, x+2.
The volume of a rectangular box is the product of its three dimensions. The volume is 138000 cm³.

The dimensions of the box are 23 cm x 24 cm x 25 cm.