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3 years ago

First right brainliest

Mathematics

2 answers:

marishachu [46]3 years ago

8 0

Answer
x= 14,-14

hope this helps and have a wonderful day :)

Mademuasel [1]3 years ago

4 0

Answer:

The answer is x=14 and x=-14

Step-by-step explanation:

x²=196

(x-14)(x+14)

x-14=0 x+14=0

x=14 x=-14

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a straight line through points p and q is drawn perpendicular to a line through points p(x,y) and r(x,(y+10)) . the possible coo

Dmitrij [34]

On the X-Y plane, the points p and r are on the vertical line X=x. Then the perpendicular (horizontal) line through p will have the equation Y=y. Points q on that line will have coordinates

... q(<anything>, y)

3 0

3 years ago

What is the y-intercept of the function, represented by the table of values

AleksandrR [38]

Answer:

Step-by-step explanation:

The table is given below

$\left|\begin{array}{c|cc}x&y\\--&--\\-2&15\\1&6\\2&3\\4&-3\\7&-12\end{array}\right|$

We can see that the table represents a linear function since by checking its slope.

Using:

Points (-2,15) and (1,6)
Points (1,6) and (2,3)

$Slope =\dfrac{6-15}{1-(-2)} =\dfrac{3-6}{2-1}=-3$

Therefore, the values represent a linear function.

A linear equation is of the form y=mx+b

Therefore:

y=-3x+b

Using the points (7,-12)

$-12=-3(7)+b\\-12=-21+b\\b=-12+21\\b=9$

Therefore, the y-intercept of the function, represented by the table of values is 9.

6 0

3 years ago

dear brainly, I hope you see this, Please be aware of when you go and delete a persons account and or questions and answers. Be

Scrat [10]

Answer:

So true bro

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that

Ivan

Answer:

$\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}$

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

Given :-

• $\sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}$

To Prove :-

• $\sf\implies cos2A =\dfrac{\sqrt3}{2}$

Proof :-

We know that ,

$\sf\implies cos2A = 1 - 2sin^2A$

Therefore , here substituting the value of sinA , we have ,

$\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2$

Simplify the whole square ,

$\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}$

Add the numbers in numerator ,

$\sf\implies cos2A = 1-2\times \dfrac{4-2\sqrt3}{8}$

Multiply it by 2 ,

$\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}$

Take out 2 common from the numerator ,

$\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}$

Simplify ,

$\sf\implies cos2A = 1 -\dfrac{ 2-\sqrt3}{2}$

Subtract the numbers ,

$\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}$

Simplify,

$\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }$

Hence Proved !

8 0

3 years ago

Please help???? Geometry

Musya8 [376]

Any line can be expresses as:

y=mx+b where m=slope=(y2-y1)/(x2-x1) and b=y-intercept (value of y when x=0)

First find the slope:

m=(2-0)/(8-0)=2/8=1/4 so we have thus far:

y=0.25x+b, we solve for b using any point on the line, (8,2)

2=0.25(8)+b

2=2+b

0=b

So the line is:

y=.25x which they might also express as y=x/4

The answer is E. (1/4)x

6 0

3 years ago

Read 2 more answers