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3 years ago

Solve for b. 5b + 8 - 2b = 7b. A 2 B.4/5 C.4/7 D.1/2

Mathematics

2 answers:

Delicious77 [7]3 years ago

7 0

Answer:

b=2

Step-by-step explanation:

5b + 8 - 2b = 7b

Combine like terms

3b+8 = 7b

Subtract 3b from each side

3b+8-3b = 7b-3b

8 = 4b

Divide each side by 4

8/4 = 4b/4

2 =b

Y_Kistochka [10]3 years ago

5 0

Answer:

b=2

Step-by-step explanation:

Simplifying

5b + 8 + -2b = 7b

Reorder the terms:

8 + 5b + -2b = 7b

Combine like terms: 5b + -2b = 3b

8 + 3b = 7b

Solving

8 + 3b = 7b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-7b' to each side of the equation.

8 + 3b + -7b = 7b + -7b

Combine like terms: 3b + -7b = -4b

8 + -4b = 7b + -7b

Combine like terms: 7b + -7b = 0

8 + -4b = 0

Add '-8' to each side of the equation.

8 + -8 + -4b = 0 + -8

Combine like terms: 8 + -8 = 0

0 + -4b = 0 + -8

-4b = 0 + -8

Combine like terms: 0 + -8 = -8

-4b = -8

Divide each side by '-4'.

b = 2

Simplifying

b = 2

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3 years ago

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Wittaler [7]

Answer:

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Step-by-step explanation:

For this case we have a 99% confidence interval for the true mean hegiht givne by:

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And we can begin finding the mean with this formula:

$\bar X= \frac{65.7 +67.3}{2}= 66.5$

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The sample size for this case is $n = 144$ then the degrees of freedom are given by:

$df = n-1= 144-1=143$

And then we can find a critical value for a 99% of confidence and 143 degrees of freedom using a significance level of 0.01 and we got:

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Then the standard error is given by:

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Now we can find the other critical value for 95% of confidence and we got:

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3 years ago

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liberstina [14]

Answer:

The sampling distribution of the sample mean is:

$\bar X\sim N(\mu_{\bar x}=2.4,\ \sigma_{\bar x}=0.40)$

Step-by-step explanation:

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Then, the mean of the distribution of sample means is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample means is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

Let X = number of cars running a red light in a day, at a given intersection.

The information provided is:

$E(X)=\mu=2.4\\SD(X)=\sigma=4\\n=100$

The sample selected is quite large, i.e. n = 100 > 30.

The Central limit theorem can be used to approximate the sampling distribution of the sample mean number of cars running a red light in a day, by the Normal distribution.

The mean of the sampling distribution of the sample mean is:

$\mu_{\bar x}=\mu=2.4$

The standard deviation of the sampling distribution of the sample mean is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{4}{\sqrt{100}}=0.40$

The sampling distribution of the sample mean is:

$\bar X\sim N(\mu_{\bar x}=2.4,\ \sigma_{\bar x}=0.40)$

8 0

3 years ago

Solve for b. 5b + 8 - 2b = 7b. A 2 B.4/5 C.4/7 D.1/2​

Solve for b. 5b + 8 - 2b = 7b. A 2 B.4/5 C.4/7 D.1/2