Find an antiderivative F(x) with F'(x) = f(x) = 11+(21x^2)+(21x^6) and F(1)=0

PLEASEEEE HURRY!! What MUST be true for a parabola that has a maximum value? (Select all that apply) a.) the leading coefficient

timama [110]

Answer:

B.)

Step-by-step explanation:

that is a characteristic of a maximum value parabola.

4 0

3 years ago

Work out 11. 28- 2.843

umka21 [38]

Answer:

25.157

Step-by-step explanation:

28-2.843=25.157

4 0

3 years ago

What eigen value for this matix <br> (1 -2)<br> (-2 0)

natali 33 [55]

You find the eigenvalues of a matrix A by following these steps:

Compute the matrix $A' = A-\lambda I$ , where I is the identity matrix (1s on the diagonal, 0s elsewhere)
Compute the determinant of A'
Set the determinant of A' equal to zero and solve for lambda.

So, in this case, we have

$A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]$

The determinant of this matrix is

$\left|\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right| = -\lambda(1-\lambda)-(-2)(-2) = \lambda^2-\lambda-4$

Finally, we have

$\lambda^2-\lambda-4=0 \iff \lambda = \dfrac{1\pm\sqrt{17}}{2}$

So, the two eigenvalues are

$\lambda_1 = \dfrac{1+\sqrt{17}}{2},\quad \lambda_2 = \dfrac{1-\sqrt{17}}{2}$

5 0

3 years ago

Read 2 more answers

PLEASE HELP QUICK QUESTION EARN 20 POINTS

slamgirl [31]

Answer: The correct option is (D) 36.

Step-by-step explanation: We are given to find the value of 'y' that would make OP parallel to LN.

MO = 28 units, OL= 14 units, Pl = 18 units and MP = y = ?

From the figure, we have

if OP ║ LN, then we must have

∠MOP = ∠MLN

and

∠MPO = ∠MNL.

Since ∠M is common to both the triangles MOP and MLN, so by AAA postulate, we get

ΔMOP similar to ΔMLN.

We know that the corresponding sides of two similar triangles are proportional, so

$\dfrac{MO}{ML}=\dfrac{MP}{MN}\\\\\\\Rightarrow \dfrac{MO}{MO+OL}=\dfrac{MP}{MP+PN}\\\\\\\Rightarrow \dfrac{28}{28+14}=\dfrac{y}{y+18}\\\\\\\Rightarrow \dfrac{28}{42}=\dfrac{y}{y+18}\\\\\\\Rightarrow \dfrac{2}{3}=\dfrac{y}{y+18}\\\\\\\Rightarrow 2y+36=3y\\\\\Rightarrow y=36.$

Thus, the required value of 'y' is 36.

(D) is the correct option.

4 0

3 years ago

Read 2 more answers

Two consecutive integers have a sum of 153. find the integers.

Natasha2012 [34]

X = first integer
x + 1 = second consecutive integer

x + (x + 1) = 153..combine like terms
2x + 1 = 153
2x = 153 - 1
2x = 152
x = 152/2
x = 76

x + 1 = 76 + 1 = 77

so ur numbers are : 76 and 77...and u will find that when added equal 153.

6 0

3 years ago