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2 years ago

These are all my points, if you can do every single question you will get 55 points

Mathematics

1 answer:

Arturiano [62]2 years ago

8 0

1) 6

2) 9

3) 7

4) 1

5) 8

6) 3

7) 0

8) 2

9) 4

10) 5

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1 year ago

Ex 4.8 14) integrate 3^(2x-1)

sesenic [268]

Take the integral:

$\large\begin{array}{l} \mathsf{\displaystyle\int\!3^{2x-1}\,dx}\\\\ =\mathsf{\displaystyle\int\!\frac{1}{2}\cdot 2\cdot 3^{2x-1}\,dx}\\\\ =\mathsf{\displaystyle\frac{1}{2}\int\!3^{2x-1}\cdot 2\,dx\qquad(i)} \end{array}$

$\large\begin{array}{l} \textsf{Substitute}\\\\ \mathsf{2x-1=u\quad\Rightarrow\quad 2\,dx=du}\\\\\\ \textsf{so (i) becomes}\\\\ =\mathsf{\displaystyle\frac{1}{2}\int\!3^u\,du}\\\\ =\mathsf{\dfrac{1}{2}\cdot \dfrac{1}{\ell n\,3}\,3^u+C}\\\\ =\mathsf{\dfrac{1}{2\,\ell n\,3}\,3^{2x-1}+C} \end{array}$

$\large\begin{array}{l} \boxed{\begin{array}{c}\mathsf{\displaystyle\int\!3^{2x-1}\,dx=\frac{1}{2\,\ell n\,3}\,3^{2x-1}+C} \end{array}}\qquad\checkmark \end{array}$

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2154165

$\large\textsf{I hope it helps. :-)}$


Tags: integrate indefinite integral substitution exponential base logarithm log ln composite integral calculus

4 0

2 years ago

Simplify the expression: -7d+5(10d+-6)

Alexandra [31]

Answer:

-7d+50d+-30= 43d+-30

Use distributive property when there is parentheses and a number infront.
combine like terms. ONLY if they have the same variable.
then just put them in an expression.

3 0

2 years ago