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2 years ago

At what rate percent will the interest on Rs. 6300 in 10 years be equal to its principal?

Mathematics

1 answer:

grin007 [14]2 years ago

6 0

Answer:

the answer is 10÷6300×100=0,16%

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slamgirl [31]

Answer:

The score is $x = 1884$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 1500$

The standard deviation is $\sigma = 300$

From the question we are told that the score follow a normal distribution

i.e $X \~ \ N( 1500 , 300)$

The proportion of score in the top 10% is mathematically

$P(X > x ) = P( \frac{X - \mu}{\sigma } > \frac{x - \mu}{\sigma } ) = 0.10$

Where x is the minimum score required to be in the top 10%

Now the $\frac{X - \mu}{\sigma } = Z (The \ Standardized \ value \ of \ X)$

$P(X > x ) = P( Z > \frac{x - \mu}{\sigma } ) = 0.10$

$P(X > x ) = P( Z > \frac{x - 1500}{300} ) = 0.10$

So the critical value of 0.10 from the normal distribution table is $Z_{0.10} = 1.28$

$\frac{x - 1500}{300} = 1.28$

$x = 1884$

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3 years ago

At what rate percent will the interest on Rs. 6300 in 10 years be equal to its principal?​

At what rate percent will the interest on Rs. 6300 in 10 years be equal to its principal?