Hey.
acc'g to the conditions :
Let Catherine has x
and James has 5 + 3x
Then,
Hence
• Catherine has = x = $9,
• and James has = 5 +3x = 5 + 3(9) = $32
Thanks.
(6, 2 )
substitute x = 5 into the equation and solve for y
6y + 8 = 20 ( subtract 8 from both sides )
6y = 12 ( divide both sides by 6 )
y = 
= 2
the ordered pair is (5, 2 )
Given:
ABCD is a quadrilateral
AC = 12, DE = 4 and FB = 5
To find:
The area of the polygon.
Solution:
AC bisects the quadrilateral into two triangles.
Area of triangle:
<u>Area of triangle DAC:</u>
Area of triangle DAC = 24 square units.
<u>Area of triangle BAC:</u>
Area of triangle BAC = 30 square units.
Area of polygon = Area of triangle DAC + Area of triangle BAC
= 24 square units + 30 square units
= 54 square units
The area of the polygon is 54 square units.
Answer:
24.075, 24.008, 21.605, 21.048
Answer:
-3
Step-by-step explanation:
5+-3 equals 2 because it is technically 5-3.
