Answer: the length of string that been let out to fly the kite this high is 172.89 ft
Step-by-step explanation:
The length of string attached to the kite, the vertical height of the kite above the ground and the ground distance forms a right angle triangle.
With an angle of 57 degrees, the length of the string that is attached to the kite represents the hypotenuse of the right angle triangle.
The height of the kite above the ground represents the opposite side of the triangle
To determine h, the length of the string that has been let out to fly the kite this high, we would apply the
Sine trigonometric ratio which is expressed as
Sine θ = opposite side/hypotenuse
Sin 57 = 145/h
h = 145/Sin57 = 145/0.8387
h = 172.89
Mischa wrote the quadratic equation 0 = –x2 + 4x – 7 in standard form
The standard form of quadratic equation is
When y=0 then the standard equation becomes
Now we compare the given equation 
with and find the value of a, b,c
-x^2 can be written as -1x^2
a= -1 , b=4 and c=-7
The value of c is -7
X=52 (vertically opposite angles)
Answer:
$643.50
Step-by-step explanation:
Let i be the profit realized from the sale and d be the discount made on the sale:
#John's selling price can be calculated by first adding profit, i to $450, the d to the new price as:
![P_n=P_o(1+i)+d[P_o(1+i)]\\=450(1+0.3)+0.1[450(1+0.3)]\\\\\\=450\times 1.3+0.1(450\times1.3)\\\\=585+58.5\\\\=643.50](https://tex.z-dn.net/?f=P_n%3DP_o%281%2Bi%29%2Bd%5BP_o%281%2Bi%29%5D%5C%5C%3D450%281%2B0.3%29%2B0.1%5B450%281%2B0.3%29%5D%5C%5C%5C%5C%5C%5C%3D450%5Ctimes%201.3%2B0.1%28450%5Ctimes1.3%29%5C%5C%5C%5C%3D585%2B58.5%5C%5C%5C%5C%3D643.50)
Hence, John will resell the bike at $643.50
Answer:
x= 42.5°
The angle shown in the figure is a right angle.
x+3x+10=180°
=>4x= 170°
=>x= 170/4= 42.5°
