<u>ANSWER:</u>
The price of senior citizen ticket is $4 and price of child ticket is $7.
<u>SOLUTION:
</u>
Given, first day of sales the school sold 3 senior citizen tickets and 9 child tickets for a total of $75.
The school took in $67 on the second day by selling 8 senior citizen tickets and 5 child tickets.
We need to find what is the price each of one senior citizen tickets and one child tickets.
Let, the price of senior citizen ticket be "x" and price of child ticket be "y"
Then according to the given information,
3x + 9y = 75
x + 3y = 25 [by cancelling the common term 3.
x = 25 – 3y ---- (1)
And, 8x + 5y = 67 ---- (2)
Substitute (1) in (2)
8(25 – 3y) + 5y = 67
200 – 24y + 5y = 67
5y – 24y = 67 – 200
-19y = -133
y = 
y = 7
Now substitute y value in (1)
x = 25 – 3(7)
x = 25 – 21 = 4
Hence, the price of senior citizen ticket is $4 and price of child ticket is $7.
Answer:
∠ XZY ≈ 23.6°
Step-by-step explanation:
Using the sine ratio in the right triangle, that is
sinXZY =
=
=
, then
∠ XZY =
(
) ≈ 23.6° ( to 1 dec. place )
Hi there!
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I believe your answer is:
4
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Here’s why:
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- I am assuming that the fraction is supposed to be the exponent.
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![64^{\frac{1}{3}}\\--------\\\rightarrow \text{Recall the exponent rule: } a^{\frac{m}{n}}=(\sqrt[n]{a})^m\\\\\\\rightarrow \sqrt[3]{64}\\\\\rightarrow \boxed{4}](https://tex.z-dn.net/?f=64%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5C%5C--------%5C%5C%5Crightarrow%20%5Ctext%7BRecall%20the%20exponent%20rule%3A%20%7D%20a%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%28%5Csqrt%5Bn%5D%7Ba%7D%29%5Em%5C%5C%5C%5C%5C%5C%5Crightarrow%20%5Csqrt%5B3%5D%7B64%7D%5C%5C%5C%5C%5Crightarrow%20%20%5Cboxed%7B4%7D)
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Hope this helps you. I apologize if it’s incorrect.
Answer:
Option B is correct.
is equivalent to 
Step-by-step explanation:
Given expression: 
Using exponents power:
Given:
Apply exponent power :
⇒ 
⇒ 
⇒
Therefore, the expression which is equivalent to
is, 
Answer:


Step-by-step explanation:
We have been given the equation:

And 
Second equation can be rewritten as:

We will solve the equations:
(1)
(2)
Multiply equation (1) by 5 and equation (2) by 3 we get:
(3)
(4)
Now, subtract (4) from (3) we get:


Now substitute
in equation (1) we get:




