<h3>
Answer: 80 meters</h3>
This is an isosceles triangle. The dashed line is the height which is perpendicular to the base 120. The height is always perpendicular to the base. The dashed line cuts the base into two equal pieces (this only works for isosceles triangles when you cut at the vertex like this).
So we have two smaller triangles each with a base of 60 and a height of x. Focus on one of the right triangles and use the pythagorean theorem to solve for x.
a^2 + b^2 = c^2
x^2 + (60)^2 = (100)^2
x^2 + 3600 = 10000
x^2 = 10000 - 3600
x^2 = 6400
x = sqrt(6400)
x = 80
Each smaller right triangle has side lengths of 60, 80, 100
Note the ratio 60:80:100 reduces to 3:4:5. A 3-4-5 right triangle is a very common pythagorean primitive.
Answer:
r=5
Step-by-step explanation:
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
-3*(4*r-8)-(-36)=0
Step by step solution :
Step 1 :
Step 2 :
Pulling out like terms :
2.1 Pull out like factors :
4r - 8 = 4 • (r - 2)
Equation at the end of step 2 :
(0 - 12 • (r - 2)) - -36 = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
60 - 12r = -12 • (r - 5)
Equation at the end of step 4 :
-12 • (r - 5) = 0
Step 5 :
Equations which are never true :
5.1 Solve : -12 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
5.2 Solve : r-5 = 0
Add 5 to both sides of the equation :
r = 5
One solution was found :
r = 5
brainliest pllzz thx god bless
Answer:
ac is parallel to df because it doesn't intersect with each other
You can make 13.5 three quarter servings
Answer:
41887.90 cubic feet
Step-by-step explanation:
We need to find the volume of the silo.
We simply need to find the volume of the cylindrical part and the conical part and add them together.
The body of the silo is a cylinder with height of 30 ft and radius of 20 ft and the roof is a cone with height 10 ft and radius 20 ft.
The volume of a cylinder is given as:
The volume of a cone is given as:
where r = radius of cylinder and cone
h = height of cylinder
H = height of cone
Adding them together, we have that the volume of the silo is:
![V = \pi r^2 (h + \frac{1}{3}H)\\ \\V = \pi * 20^2 (30 + [\frac{1}{3}* 10]) \\\\V = 1256.64 ( 30 + 3.33)\\\\V = 1256.64(33.33)\\\\V = 41887.90 ft^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cpi%20r%5E2%20%28h%20%2B%20%5Cfrac%7B1%7D%7B3%7DH%29%5C%5C%20%5C%5CV%20%3D%20%5Cpi%20%2A%2020%5E2%20%2830%20%2B%20%5B%5Cfrac%7B1%7D%7B3%7D%2A%2010%5D%29%20%5C%5C%5C%5CV%20%3D%201256.64%20%28%2030%20%2B%203.33%29%5C%5C%5C%5CV%20%3D%201256.64%2833.33%29%5C%5C%5C%5CV%20%3D%2041887.90%20ft%5E3)
The volume of the silo is 41887.90 cubic feet.
