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dem82 [27]
3 years ago
12

FIRST TO HELP IS BRAINLIEST

Mathematics
1 answer:
Julli [10]3 years ago
7 0

Answer:

(0,2)

Step-by-step explanation:

You might be interested in
What is the height of the prism if there is 30 square centimeters and the volume is 90 cubic centimeters
sammy [17]

Answer:

the height of the prism =3cm

Step-by-step explanation:

From the question :there is 30 square centimeters, we can deduce this is the area due to the unit

the volume is 90 cubic centimeters

Volume of prism = Area of base × height

We are to determine the height

90cm³ = 30cm² × height

divide both sides by 30cm²

height = 90cm³/30cm²

height = 3cm

Therefore the height of the prism is 3centimeters

8 0
3 years ago
Help me please... I have a lot more things to do and I wanna get this done.
lianna [129]

Answer:

-6

Step-by-step explanation:

count

7 0
3 years ago
Read 2 more answers
1/3x(-6+27y-51z)simplify
Naya [18.7K]
Final result :

9y - 17z - 2
Step by step solution :

Step 1 :

1
Simplify —
3
Equation at the end of step 1 :

1
— • (27y - 51z - 6)
3
Step 2 :

Pulling out like terms :

3.1 Pull out like factors :

27y - 51z - 6 = 3 • (9y - 17z - 2)

Final result :

9y - 17z - 2
8 0
3 years ago
Read 2 more answers
PLEASE HELP SHOW YOUR WORKING OUT Branliest
Ad libitum [116K]

Answer:

The equation of this line is therefore    y = 2x + 3.

Step-by-step explanation:

this line passes thru the points (0, 3) and (3, 9).  As we move from  (0, 3) to (3, 9), x increases by 3 and y increases by 6.  Thus, the slope of this line is

m = rise / run = 6/3, or m = 2.  Inserting the known info (m = 2, x = 0, y = 3) into y = mx + b, we get:  3 = 2(0) + b, so we see that b = 3.

The equation of this line is therefore    y = 2x + 3.

5 0
3 years ago
If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.
alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]

The inverse of the matrix is

\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]

So, the Inverse Transformation is given by

T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

So, no option is correct. And the answer is

T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

Learn more about linear transformations here-

brainly.com/question/13005179

#SPJ10

5 0
2 years ago
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