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Leokris [45]
3 years ago
12

Convert x2 + y2 -4x = 0 to polar form.

Mathematics
1 answer:
Bingel [31]3 years ago
7 0

Answer:

r(r-4\cos \theta)=0

Step-by-step explanation:

We are given the following equation:

x^2 + y^2 -4x = 0

We have to convert it into polar form.

We put

x = r \cos \theta\\y = r\sin \theta

Putting values, we get:

x^2 + y^2 -4x = 0\\(r\cos \theta)^2 + (r\sin \theta)^2 - 4(r\cos \theta) = 0\\r^2(\cos^2 \theta + \sin^2 \theta) - 4r\cos \theta = 0\\r^2 - 4r\cos \theta = 0\\r(r-4\cos \theta)=0

is the required polar form.

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