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Olin [163]
2 years ago
14

Al these are benefits of computer literacy except

Computers and Technology
1 answer:
Harrizon [31]2 years ago
8 0

Explanation:

  • Being computer literate supports entrepreneurship. ...
  • Communication. ...
  • Enhance your employment opportunities. ...
  • Address the gap in your knowledge. ...
  • Computers Reconstruct Business
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All resources are limited. Which of the following is NOT a resource?
gladu [14]
The appropriate answer is C ! all other are very limited but labour can be increased or decreased according to our will and it doesn't exhaust !
3 0
3 years ago
Write a program that computes the monthly net pay of the employee for a steel factory. The input for this program is the hourly
Mars2501 [29]

Answer:

#include<stdio.h>

int main()

{

float rate_of_pay,regular_hours,overtime_hours,grosspay,netpay,tax;

printf("Enter the Hourly rate of pay : ");

scanf("%f",&rate_of_pay);

printf("Enter the number of Regular hours : ");

scanf("%f",&regular_hours);

printf("Enter the number of Overtime hours : ");

scanf("%f",&overtime_hours);

grosspay=(regular_hours*rate_of_pay)+(1.5*overtime_hours*rate_of_pay);

netpay=grosspay-(grosspay*0.2);

printf("Employee's Gross pay = %f\n",grosspay);

printf("Tax = %f\n",0.2*grosspay);

printf("Employee's Net pay = %f\n",netpay);

return 0;

}

Note: The variables are declared as float, to support partial hours like 0.5,6.5 etc.

Explanation:

6 0
3 years ago
The following checksum formula is widely used by banks and credit card companies to validate legal account numbers: d0 + f(d1) +
Aleksandr [31]

Answer:

Here is the JAVA program:

import java.util.Scanner; //to import Scanner class

public class ISBN

{   public static void main(String[] args)  { // start of main() function body

   Scanner s = new Scanner(System.in); // creates Scanner object

//prompts the user to enter 10 digit integer

   System.out.println("Enter the digits of an ISBN as integer: ");    

   String number = s.next(); // reads the number from the user

   int sum = 0; // stores the sum of the digits

   for (int i = 2; i <= number.length(); i++) {

//loop starts and continues till the end of the number is reached by i

          sum += (i * number.charAt(i - 1) ); }

/*this statement multiplies each digit of the number with i and adds the value of sum to the product result and stores in the sum variable*/

          int remainder = (sum % 11);  // take mod of sum by 11 to get checksum  

   if (remainder == 10)

/*if remainder is equal to 10 adds X at the end of given isbn number as checksum value */

  { System.out.println("The ISBN number is " + number + "X"); }

  else

// displays input number with the checksum value computed

 {System.out.println("The ISBN number is " + number + remainder); }  }  }  

Explanation:

This program takes a 10-digit integer as a command line argument and uses Scanner class to accept input from the user.

The for loop has a variable i that starts from 2 and the loop terminates when the value of i exceeds 10 and this loop multiplies each digit of the input number with the i and this product is added and stored in variable sum. charAt() function is used to return a char value at i-1.

This is done in the following way: suppose d represents each digit:

sum=d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5 + d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9

Next the mod operator is used to get the remainder by dividing the value of sum with 11 in order to find the checksum and stores the result in remainder variable.

If the value of remainder is equal to 10 then use X for 10 and the output will be the 10 digits and the 11th digit checksum (last digit) is X.

If the value of remainder is not equal to 10, then it prints a valid 11-digit number with the given integer as its first 10 digits and the checksum computed by sum % 11 as the last digit.  

8 0
3 years ago
What does the use of color and images on a blog refer to?
serious [3.7K]
I think marketing and branding. i dont think this is 100% correct
8 0
3 years ago
Read 2 more answers
Finish this for brainliest and 30 points
n200080 [17]
What do you mean what are we supposed to finish

6 0
2 years ago
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