ΔJKL, sin(JLK)=JK/KL=3/6=0.5
<JKL=30deg.
cos(JLK)=JL/KL
JL=KL*cos(JLK)=6cos(30deg.)
<JLK + <JLM = <MLK
30 + <JLM = 61
<JLM=31deg
in ΔMJL
tan(JLM)=JM/JL
JM=JL*tan(JLM)
=6cos(30deg.)*tan(31deg)
=3.12
The distance between (-22,15) and (30,-25) is 4√269 ≈ 65.6
Answer:
the answer is let a b* ban me
Step-by-step explanation:
Answer:
<h2>H = 3</h2>
Step-by-step explanation:
