You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2
y = (x - 3)/((x - 1)(x - 3)) + 2
Answer:
<h2><em>
38°, 66° and 76°</em></h2>
Step-by-step explanation:
A triangle consists of 3 angles and sides. The sum of the angles in a triangle is 180°. Let the angle be <A, <B and <C.
<A + <B + <C = 180° ...... 1
If the measure of one angle is twice the measure of a second angle then
<A = 2<B ...... 2
Also if the third angle measures 3 times the second angle decreased by 48, this is expressed as <C = 3<B-48............ 3
Substituting equations 2 and 3 into 1 will give;
(2<B) + <B + (3<B-48) = 180°
6<B- 48 = 180°
add 48 to both sides
6<B-48+48 = 180+48
6<B = 228
<B = 228/6
<B =38°
To get the other angles of the triangle;
Since <A = 2<B from equation 2;
<A = 2(38)
<A = 76°
Also <C = 3<B-48 from equation 3;
<C = 3(38)-48
<C = 114-48
<C = 66°
<em>Hence the measures of the angles of the triangle are 38°, 66° and 76°</em>
The answer is 0.04 (I hope). Here is an explanation:
Hi! Ok so you use PEMDAS to figure these out.
So first we can cancel out parenthesis and exponents since there are none in this equation.
Now we do multiply and divide from left to right.
So first 18/3=6
So 6+6*4
Now we do 6*4=24
Now add and subtract
Then 6+24=30
So your answer is 30
