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77julia77 [94]
3 years ago
13

What is the process of changing from one form to another

Mathematics
2 answers:
Darina [25.2K]3 years ago
8 0

Answer:

It is called transformation

Rashid [163]3 years ago
7 0

The process of changing from one form to another is called transformation

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Factor x^2 -2x -15<br> need help
Ann [662]

Answer:

x=5

Step-by-step explanation:

3 0
3 years ago
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What is the equation of the line that passes through the point (-2, 0) and has
garik1379 [7]

Answer:

y = 2x + 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2 , then

y = 2x + c ← is the partial equation

To find c substitute (- 2, 0 ) into the partial equation

0 = - 4 + c ⇒ c = 0 + 4 = 4

y = 2x + 4 ← equation of line

8 0
3 years ago
A 64-ounce container of coconut milk costs 3.32. A 120-ounce container of the same milk costs 5.90
Marysya12 [62]

Answer: It would be cheaper to by the 120 ounce, instead of two 64 ounces.

Step-by-step explanation:

That’s because it would be $6.64, for two 64 ounces. $5.90 is cheaper than $6.64. Therefore it would be cheaper to get the 120 ounce.

5 0
4 years ago
In a large population, 60% of the people have been vaccinated. If 4 people are randomly selected, what is the probability that A
gulaghasi [49]

Answer:

0.9744 probability that AT LEAST ONE of them has been vaccinated

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have been vaccinated, or they have not. The probability of a person having been vaccinated is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

60% of the people have been vaccinated.

This means that p = 0.6

If 4 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated?

This is

P(X \geq 1) when n = 4.

We have that

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.6)^{0}.(0.4)^{4} = 0.0256

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0256 = 0.9744

0.9744 probability that AT LEAST ONE of them has been vaccinated

5 0
3 years ago
Simplify the expression (x^19 y^21)^4/(x^2 y^6)^2<br><br> The simplified expression is ________.
Masja [62]
I got x^72y^72 i hope this helps

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3 years ago
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