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I am Lyosha [343]
2 years ago
13

One pizza is $12 and a cake is $18. If Matt has $84, how many pizzas can he buy at most and still afford to buy a cake

Mathematics
2 answers:
Ray Of Light [21]2 years ago
7 0

Answer:

5

Step-by-step explanation:

To find the number of pizzas Matt can buy while still being able to afford a cake set up an inequality. The inequality should look like 84\geq 12x+18  where x is the number of pizzas Matt bought. Then, solve the inequality by first subtracting 18 from both sides, 66\geq 12x. Next, divide both sides by 12, 5.5\geq x. This means that Matt can buy 5 pizzas. At first, it might seem like you should round up; however, if you rounded up at all then Matt could not afford the cake, so you must round down.

ki77a [65]2 years ago
4 0

Answer:

5 pizzas

Step-by-step explanation:

So first you subtract 18 so that you know that there is at least one cake.

84 - 18 = 66

When you get 66 dollars remaining, you divide it by 12 to see how many you can afford.

66/12 = 5.5

So because you can’t say you have an additonal amount of money, you would actually round down to 5.

So Matt can buy a total of 5 pizzas and 1 cake.

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bixtya [17]

∑Hey , jillianwagler ⊃

Answer:

x = 7, y = -5

Step-by-step explanation:

<u><em>Given~:</em></u>

<em>Solve the system below using elimination</em>

<em>{5x+9y= -10}</em>

<em>{7x+10y= -1}</em>

<u><em>Solve:</em></u>

<u><em></em></u>\begin{bmatrix}5x+9y=-10\\ 7x+10y=-1\end{bmatrix}

Isolate x ( 5x + 9y = -10 ) : \mathrm{x=\frac{-10-9y}{5}}

Substitute: \mathrm{x=\frac{-10-9y}{5}}

\begin{bmatrix}7\cdot \frac{-10-9y}{5}+10y=-1\end{bmatrix}

\begin{bmatrix}\frac{-70-13y}{5}=-1\end{bmatrix}

Isolate y : \frac{-70-13y}{5}=1:y=-5

Substitute: y=-5

x=\frac{-10-9\left(-5\right)}{5}=7

Hence, x=7

Therefore, the solution for \begin{bmatrix}5x+9y=-10\\ 7x+10y=-1\end{bmatrix} are:

x=7,\:y=-5

<u><em>xcookiex12</em></u>

<u><em></em></u>

<em>8/19/2022</em>

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cluponka [151]

Answer:

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Step-by-step explanation:

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