Depends on how far away the event is and what the temperature is as this affects the speed of sound.
For example, let's say you're 600 meters away and the temperature has no affect.
The speed of sound would be roughly 340 m/s so the time it would take to hear the sound would be 600/340 = 1.76 seconds
The speed of light (c) is 3.0 X 10^8 m/s so the time it would take to see the event would be 600/3 X 10^8 = 2 X 10^-7
Subtract: 1.76 - (2 X 10^-7) = approx. 1.76
Answer:
The new period will be √6 *T
Explanation:
period ,T=2π√(L/g) ................equation 1
where T is the period on earth
gravitational acceleration on the moon is g/6
T1 = 2π√[L/(g/6)]
T1=2π√(6L/g) ...............equation 2
divide equation 2 by 1
T1/T =2π√(6L/g)÷2π√(L/g)
T1/T =√(6L/L)
T1/T =√6
T1 = √6 *T
A. B. D. C. D, A, A, C, B, B, D, D
Answer:
The capacitance of the deflecting plates is 
.
Explanation:
The expression for the capacitance of the capacitor in terms of area and distance is as follows;
Here, C is the capacitance, A is the area, d is the distance and 
is the absolute permittivity.
Convert the side of the square from cm to m.
s= 3.0 cm
s= 0.030 m
Calculate the area of the square.
Put s= 0.030 m.
Convert distance from mm to m.
d= 5.0 mm
Calculate the capacitance of the deflecting plates.
Put , and 
.
Therefore, the capacitance of the deflecting plates is .
