The power that the light is able to utilize out of the supply is only 0.089 of the given.
Power utilized = (0.089)(22 W)
= 1.958 W
= 1.958 J/s
The energy required in this item is the product of the power utilized and the time. That is,
Energy = (1.958 J/s)(1 s) = 1.958 J
Thus, the light energy that the bulb is able to produce is approximately 1.958 J.
Answer:d
Explanation:
Alpha particles are heaviest among alpha, beta and gamma so they have least amount of Penetration compared to both.
Gamma Particles are lightest among three so they can Penetrate most .
The order of Penetration is given by
Alpha< Beta < Gamma
