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Y_Kistochka [10]
3 years ago
15

What muscle are controlled by the autonomic muscle system and are involuntary

Physics
2 answers:
FromTheMoon [43]3 years ago
4 0
The answer is smooth muscle, Hope this helped! Have a good day!
evablogger [386]3 years ago
3 0
Smooth muscle is the answer.
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The strength of the electric field 0.5 m from a 6 uC charge is
Triss [41]

Answer:

E= 2.158× 10*5N/C

Explanation:

K= 8.99×10*9, q= 6×10*-6C, d= 0.5m

E= kq/d*2

E= (8.99×10*9× 6×10*-6)/0.5*2

E= 215760

E= 2.158 ×10*5N/C

5 0
3 years ago
What is electric charge ?​
Alenkasestr [34]
DescriptionElectric charge is the physical property of matter that causes it to experience a force when placed in an electromagnetic field. There are two types of electric charge: positive and negative. Like charges repel and unlike attract. An object with an absence of net charge is referred to as neutral.
6 0
3 years ago
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A student needs to prepare 100.0 mL of vitamin C solution according to the directions in Part 1 of the experiment. S/he weighs o
Rudiy27

Answer:

4.99 mg of vitamin C are in the beaker.

Explanation:

Given that,

Weight of vitamin = 0.0499 g

Molar mass = 176.124 g/mol

Weight of water = 100.0 ml

We need to calculate the mg of vitamin C in the beaker

We dissolve 0.0499 g vitamin C in water to from 100.0 ml solution.

100 ml solution contain 49.9 mg vitamin C

Now, we take 10 ml of this vitamin C solution in breaker

Since, 100 ml solution =49.9 mg vitamin C

Therefore,

10\ ml\ solution =\dfrac{10\times49.9}{100}

10\ ml\ solution =4.99\ mg

Hence, 4.99 mg of vitamin C are in the beaker.

4 0
3 years ago
Two blocks are connected by a light string that passes over two frictionless pulleys. The block of mass m2 is attached to a spri
irina1246 [14]

(BELOW YOU CAN FIND ATTACHED THE IMAGE OF THE SITUATION)

Answer:

d=\frac{2g(m1-m2)}{k}

Explanation:

For this we're going to use conservation of mechanical energy because there are nor dissipative forces as friction. So, the change on mechanical energy (E) should be zero, that means:

E_{i}=E_{f}

K_{i}+U_{i}=K_{f}+U_{f} (1)

With K_{i} the initial kinetic energy, U_{i} the initial potential energy, K_{f} the final kinetic energy and U_{f} the final potential energy. Note that initialy the masses are at rest so K_{i} = 0, when they are released the block 2 moves downward because m2>m1 and finally when the mass 2 reaches its maximum displacement the blocks will be instantly at rest so K_{f} =0. So, equation (1) becomes:

U_{i}=U_{f} (2)

At initial moment all the potential energy is gravitational because the spring is not stretched so U_{i}=U_{gi} and at final moment we have potential gravitational energy and potential elastic energy so U_{f}=U_{gf}+U_{ef}, using this on (2)

U_{gi}=U_{gf}+U_{ef} (3)

Additional if we define the cero of potential gravitational energy as sketched on the figure below (See image attached), U_{gi}=0 and we have by (3) :

0= U_{gf}+U_{ef} (4)

Now when the block 1 moves a distance d upward the block 2 moves downward a distance d too (to maintain a constant length of the rope) and the spring stretches a distance d, so (4) is:

0=-m1gd+m2gd+\frac{kd^{2}}{2}

dividing both sides by d

0=-m1g+m2g+\frac{kd}{2}

g(m1-m2)= \frac{kd}{2}

d=\frac{2g(m1-m2)}{k}, with k the constant of the spring and g the gravitational acceleration.

7 0
3 years ago
The rate at which light energy is radiated from a source is measured in which of the following units?
Over [174]
The correct option is D.
Lumen is used to quantify the amount of total light energy that a source is putting out in all direction, thus, it refers to luminous output of a light source. Initial lumen refers to the luminosity of a light when it was first turned on; the luminosity is highest at this point. 
3 0
3 years ago
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