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timurjin [86]
3 years ago
9

Explain why a law is accepted as facr, but a theory is not​

Physics
1 answer:
Verizon [17]3 years ago
3 0

Answer:

Explanation:

A law and theory are distinct levels in the scientific method. They do not lead to one another.

A law is a description of an observed phenomenon in the natural world. Laws are always true and do not provide explanations as to why they hold true.

A theory is an explanation of an observed phenomenon. It is usually based on experimental evidence and bounded most time in the limits of available data.

  • A law cannot be deposed. It is a fact and holds true at all times.
  • Theories can be discarded even with new technological advancements that provides a new way of study.
  • This is why it is not a fact.
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Q\;(\text{total charge of the solid sphere})=(26\;\mathrm{\mu C})\left(\dfrac{1\;\mathrm{C}}{10^6\;\mathrm{\mu C}} \right)={26\times 10^{-6}\;\mathrm{C}}

Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:

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E&=\dfrac{24\times 10^{-6}}{4\pi (8.8542\times 10^{-12})(0.6)}\\ &={6.49\times 10^5\;\mathrm{N/C}\;\text{directed radially outward}}}

The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.

As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).

Learn more about Gaussian sphere here:

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