Answer: yellow
When you mix solutions of lead (II) nitrate and potassium iodide. The precipitate is yellow in colour and the compound is lead (II) Iodide. Pb (NO3)2(aq) + 2KI(aq) → PbI2(s) + 2KNO3(aq). Yes, it is a double displacement reaction.
Explanation: The lead nitrate solution contains particles (ions) of lead, and the potassium iodide solution contains particles of iodide. When the solutions mix, the lead particles and iodide particles combine and create two new compounds, a yellow solid called lead iodide and a white solid called potassium nitrate. When a solution of potassium iodide is added to a solution of lead nitrate taken in a test tube, the precipitation of a yellowish solid is observed. This yellowish solid is lead iodide. Potassium nitrate is formed along with lead iodide. When lead nitrate is mix with potassium iodine, a precipitation reaction occurs and yellow precipitate of lead iodide is formed.
Given 3.72 g of P and 21.28g of Cl, converting these to moles: ( 3.72 g P)(mol P/30.97 g P) = 0.12 mol P (21.28 g Cl)(mol Cl/35.45 g Cl) = 0.60 mol Cl P:Cl = 0.12/0.60, therefore P: Cl =1/5 Therefore, PCl5 hope it helps
It's a mixture becuase it is a substance made by mixing other substances togrther such as flour, sugar, and eggs.
<h3>Answer:</h3>
Option-C: HCl + H₂O → H₃O⁺ + Cl⁻
Explanation:
Bronsted-Lowery concept of Acid and Base defines Acid as that specie which tends to donate H⁺ (Hydrogen Ion) and bases are those species which accepts H⁺ from Acids.
In selected option, HCl is reacting as Acid as it donates H⁺ to water (lowery bronsted base).
Also, the correspong acid is converted into conjugate base (i.e. Cl⁻) and base is converted into conjugate acid (i.e. H₃O⁺)