Transformation in chemistry is scientifically used to explain the process of changing one compound to another in a chemical reaction.
<h3>What is transformation?</h3>
The word "transformation" has a very special significance in chemistry. We know that in English, to transform would simply imply to change from one form to another. This is not quite far from its meaning in the parlance of chemistry.
The word transformation is normally applied in the area of chemical reactions especially as it has to do with reaction with in organic chemistry. It has to do with the change from one molecule to another and this is of great importance in the discussion of synthetic chemistry.
As such, the word transformation in chemistry is scientifically used to explain the process of changing one compound to another in a chemical reaction.
Learn more about chemical transformation:brainly.com/question/8210521
#SPJ1
Answer:
D. 7
Explanation:
The halogens are found in Group 7 of the Periodic Table. If Bromine is a halogen, then that means it would be found in Group 7. Also, elements in Group 7 have 7 electrons in its outer shell, Bromine would have 7 electrons in its outer shell.
Answer:
4.285 L of water must be added.
Explanation:
Hello there!
In this case, for this dilution-like problems, we need to figure out the final volume of the resulting solution so that we would be able to obtain the correct volume of diluent (water) to be added. In such a way, we can obtain the final volume, V2, as shown below:

Thus, by plugging in the initial molarity, initial volume and final molarity (0.587 M) we obtain:

It means we need to add:

Of diluent water.
Regards!
Answer: Empirical formula is 
Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.
<u>Step 1 :</u> Converting each of the given masses into their moles by dividing them by Molar masses.

Molar mass of Carbon = 12.0 g/mol
Molar mass of Hydrogen = 1.0 g/mol
Molar mass of Oxygen = 16.0 g/mol
Moles of Carbon = 
Moles of Hydrogen = 
Moles of Oxygen = 
<u>Step 2: </u>Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value
Smallest number of moles = 13.76 moles



<u>Step 3:</u> Now, the moles ratio of the elements are represented by the subscripts in the empirical formula
Empirical formula becomes = 