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2 years ago

Please help fast, I will give brainliest.

Chemistry

1 answer:

frez [133]2 years ago

7 0

Answer:

The reaction is favorable at all temperatures

Explanation:

Since G = H - TS, -H and +S would result in G = -H -TS, which will always be negative.

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In cellular respiration, living things use sugar to produce energy.<br> True or false

wel

I pretty sure it true I’m not completely sure

3 0

2 years ago

Copper(II) sulfate forms a bright blue hydrate with the formula CuSO 4 ⋅ n H 2 O ( s ) . If this hydrate is heated to a high eno

Arada [10]

Answer:

The value of n in the hydrate formula is 5 , $CuSO_4.5H_2O$ .

Explanation:

$CuSO_4.nH_2O\rightarrow CuSO_4+nH_2O$

Mass of hydrate of copper sulfate = 14.220 g

Moles of hydrate of copper sulfate = $\frac{14.220 g}{(159.5+n\times 18) g/mol}$

Mass of copper sulfate after heating = 8.9935 g

Moles of copper sulfate = $\frac{8.9935 g}{159.5 g/mol}$

$\frac{14.220 g}{(159.5+n\times 18) g/mol}=\frac{8.9935 g}{159.5 g/mol}$

Solving for n, we get:

n = 5

The value of n in the hydrate formula is 5 , $CuSO_4.5H_2O$ .

5 0

3 years ago

Atoms of oxygen have a total of 8 electrons. are these atoms stable, and why or why not? view available hint(s) atoms of oxygen

pychu [463]

No. Because only 6 valence

6 0

3 years ago

A buffer solution is made using a weak acid, HA. If the pH of the buffer is 9 and the ratio of A– to HA is 100, what is the pKa

sdas [7]

To calculate the pKa of the weak acid, we use the Henderson-Hasselbalch equation. It is expressed as pH = pKa - log [HA]/[A-]. This equation takes into account the concentration of the substance that does not dissociates into ions since it is a weak acid. We caculate as follows:

pH = pKa - log [HA]/[A-]
9 = pKa - log 1/100
pKa = 7

3 0

3 years ago

If 185 mg of acetaminophen were obtained from a tablet containing 350 mg of acetamino- phen, what would be the weight percentage

Alex73 [517]

Percentage recovery gives us an idea of the amount of pure substance recovered after the chemical reaction. Percentage recovery can be more than 100 % or less than 100 %. Usually, in any experiment performed the weight percentage recovery will be less than 100. Percent recovery values greater than 100 show that the recovered compound is contaminated.

Amount of acetaminophen initially taken = 350 mg

Amount of acetaminophen obtained after recovery =185 mg

$Weight percentage recovery =\frac{mass recovered}{mass originally taken}*100$

= $\frac{185 mg}{350 mg}*100$

= 52.9%

8 0

3 years ago