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allochka39001 [22]
2 years ago
15

Lin runs 2 3/4 miles in 2/5 of an hour. Tlyer runs 8 2/3 miles in 4/3 of an hour. How long does it take for each of them to run

10 miles
Mathematics
1 answer:
Shalnov [3]2 years ago
3 0

Answer:

Lin 1.454 h

Noah 1.54h

Step-by-step explanation:

From the above, we were given that;

Lin ran 2 3/4 miles in 2/5 an hour. Then, Noah ran 8 2/3 miles in 4/3 an hour

Speed of Lin

V = [(2 3/4)/(2/5)] mph

V = [(11/4)/(2/5)] mph

V = 6.875mph

Speed of Noah

V = [(8 2/3)/(4/3)] mph

V = [26/3)/(4/3))] mph

V = 6.5mph

The time taken by Lin to cover 10 miles

t = 10/6.875

t = 1.454h

The time taken by Noah to cover 10 miles

t = 10/6.5

t = 1.54h

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Answer:

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Step-by-step explanation:

The missing parameters are:

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This implies that we calculate m(c(a))

We have:

c(a) = 4.25a

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m(c) = 1.15c can be written as:

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m(c(a)) = 1.15*4.25a

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Answer:

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Step-by-step explanation:

Convert this Quadratic Equation to Vertex Form by completing the square, \displaystyle y = a[x - h]^2 + k:

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So as you can see, each time we broke the equation down, we used the formula \displaystyle [\frac{b}{2}]^2 to complete the square.

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Given: The time taken to do each activity from Colin's house to his hotel in given.

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So, 45+90+70+20+35 = 260 minutes

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