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tekilochka [14]
3 years ago
12

What is the area of the triangle?

Mathematics
1 answer:
Elden [556K]3 years ago
7 0

Answer:

1.A. 75 m sq

2.D. 67.5 m sq

3.C. 210 m sq

Step-by-step explanation:

no step by step

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Factor Completely: 12x2 + 22x + 6 A) (2x+ 3)(6x + 2) B) 6(x + 1)(2x + 1) C) 2(2x + 3)(3x + 1) D) 2(2x + 1)(3x + 3)
tia_tia [17]

Answer:

C) 2 (2x + 3) (3x + 1)

Step-by-step explanation:

12x² + 22x + 6

2 ( 6x² + 11x + 3 )

2 [ 6x² + 9x + 2x + 3 ]

2 [ 3x ( 2x + 3 ) + 1 ( 2x + 3 ) ]

2 ( 2x + 3 ) ( 3x + 1 )  ⇒ C

7 0
4 years ago
Select the correct answer from each drop-down menu. The table lists the speeds of the fastest roller coasters in North America a
dangina [55]

Answer:

the answer is

6.41

12.78

17.226

Step-by-step explanation:

7 0
3 years ago
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Factor -1/4 out of -1/2x -5/4y. (i will mark brainlyest)
mash [69]

Answer:

-1/4 (2x - 5y)

Step-by-step explanation:

For us to factor -1/4 out of -1/2x -5/4y

We will have to multiply the values in bracket by the reciprocal of -1/4 i.e -4 as shown

-1/2x - 5/4 y

= -1/4 (-4(-1/2x) - (-4)(-5/4y))

= -1/4 (4/2 x - 20/4 y)

= -1/4 (2x - 5y)

Hence the factored expression is -1/4 (2x - 5y)

5 0
3 years ago
The annual interest rate of Mike's savings account is 4.8%, and simple interest is calculated monthly. What is the periodic inte
Reptile [31]

The correct option will be: d. 0.4%

For finding the periodic interest rate , we need to divide the annual interest rate by the number of times interest calculated in a year.

Here, the simple interest is calculated monthly, that means the number of times interest calculated in a year will be 12.

Annual interest rate is 4.8%

So, the periodic interest rate = \frac{4.8}{12}= 0.4%

5 0
3 years ago
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The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi
slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}

Now for the initial condition the value of C is calculated as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16

So the solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}

Simplifying the equation as

y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}

So the correct option is 4

8 0
3 years ago
Read 2 more answers
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