Answer:
Please check the attachment.
for the assembly language program the jump and move keywords have been used to establish the if else ladder.
Also for the best three marks, we need to store the three theory and two practical marks in an array, and then we can sort it to get the best three marks to find the CA. and then from initial array, we can find the last two practical test parks, and find their average.
Rest of the calculation is as being mentioned in the image. Also, in the image we have 2 practicals. We need to count two instead of three there, and rest is as shown.
Explanation:
The answer does not require any further explanation.
Answer:
ljb lih lug outbpiyougvotvoy
outiyfiyfiyfiyffiyvitfurcutfcutcrcutfutcdu
Explanation:
didn't understand the question
Answer:
SELECT Count(order_invoice) as number_of_invoices, Max(order_invoice) as maximum_invoice, Min(order_invoice) as minimum_invoice, Avg(order_invoice) as average_invoice
FROM vendor JOIN invoice ON invoice.id = vendor.id
WHERE order_invoice > 1
ORDER BY number_of_invoices DESC
Explanation:
The select statement of the SQL or structured query language returns twelve rows of four columns from the inner join of the vendor and invoice table in a database where the order_invoice column in the invoice table is greater than one. The result of the query is ordered by the alias column "number_of_invoices" in descending order.
You can go into your bedroom on a dark night, then close your eyes, and press your face into the pillow. You will then see an exact copy of the image, in perfect detail.