Answer:
miles_gallon = float(input("Enter car's miles/gallon: "))
dollars_gallon = float(input("Enter gas dollars/gallon: "))
print("Gas cost for 20 miles is $", (20 / miles_gallon) * dollars_gallon)
print("Gas cost for 75 miles is $", (75 / miles_gallon) * dollars_gallon)
print("Gas cost for 500 miles is $", (500 / miles_gallon) * dollars_gallon)
Explanation:
*The code is in Python.
Ask the user to enter the car's miles/gallon and gas dollars/gallon
Calculate the gas cost for 20 miles, divide 20 by miles_gallon and multiply the result by dollars_gallon, then print it
Calculate the gas cost for 75 miles, divide 75 by miles_gallon and multiply the result by dollars_gallon, then print it
Calculate the gas cost for 500 miles, divide 500 by miles_gallon and multiply the result by dollars_gallon, then print it
You should really state what language you are using. I have produced your method in C#, and should be easily translatable in to any other language.
static void RotateRight<T>(T[] arr)
{
T temp = arr[arr.Length - 1];
for (int i = arr.Length - 1; i >= 0; i--)
{
if (i == 0)
arr[i] = temp;
else
arr[i] = arr[i - 1];
}
}
int IsAbundant(int n)
{
int divisorSum = 0;
for (int i = 1; i < n; i++) {
if ((n % i) == 0) {
divisorSum += i;
}
}
return divisorSum > n;
}
int main()
{
int number = 0;
do {
printf("Enter a number (0 to quit): ");
scanf_s("%d", &number);
if (IsAbundant(number)) {
printf("%d is abundant!\n", number);
} else
{
printf("%d is not abundant.\n", number); }
} while (number > 0);
return 0;
}
