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lina2011 [118]
2 years ago
14

???????????.............​

Mathematics
1 answer:
inn [45]2 years ago
5 0

Answer:

Sorry but I can't read the image

Step-by-step explanation:

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A large fish tank at an aquarium needs to be emptied so that it can be cleaned. When its
VikaD [51]

Answer:

The draining time when only the big drain is opened is 2.303 hours.

The draining time when only the small drain is opened is 5.303 hours.

Step-by-step explanation:

From Physics, we know that volume flow rate (\dot V), measured in liters per hour, is directly proportional to draining time (t), measured in hours. That is:

\dot V \propto \frac{1}{t}

\dot V = \frac{k}{t} (Eq. 1)

Where k is the proportionality constant, measured in liters.

From statement, we have the following three expressions:

(i) <em>Large and small drains are opened</em>

\dot V_{s}+\dot V_{l} = \frac{k}{2} (Eq. 2)

\frac{\dot V_{s}+\dot V_{l}}{k} = \frac{1}{2}

(ii) <em>Only the small drain is opened</em>

\dot V_{s} = \frac{k}{t_{l}+3} (Eq. 3)

\frac{\dot V_{s}}{k} = \frac{1}{t_{l}+3}

(iii) <em>Only the big drain is opened</em>

\dot V_{l} = \frac{k}{t_{l}} (Eq. 4)

\frac{\dot V_{l}}{k}  = \frac{1}{t_{l}}

By applying (Eqs. 3, 4) in (Eq. 2) and making some algebraic handling, we find that:

\frac{1}{t_{l}+3}+\frac{1}{t_{l}} = \frac{1}{2}

\frac{t_{l}+t_{l}+3}{t_{l}\cdot (t_{l}+3)} = \frac{1}{2}

2\cdot t_{l}+3 = t_{l}^{2}+3\cdot t_{l}

t_{l}^{2}-t_{l}-3 = 0 (Eq. 5)

Whose roots are determined by the Quadratic Formula:

t_{l,1}\approx 2.303\,h and t_{l,2} \approx -1.302\,h

Only the first roots offers a solution that is physically reasonable. Hence, the draining time when only the big drain is opened is 2.303 hours. And the time needed for the small drain is calculated by the following formula:

t_{s} = 2.303\,h+3\,h

t_{s} = 5.303\,h

The draining time when only the small drain is opened is 5.303 hours.

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3 years ago
What number is 264 greater than 682
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926 is greater than 682
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3 years ago
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Which equation best describes the pattern in the table below?
mash [69]
If i looked at this correctly i believe the answer would be c
4 0
3 years ago
State the converse, contrapositive, and inverse of each of these conditional statements a) If it snows tonight, then I will stay
marissa [1.9K]

Step-by-step explanation:

Consider the provided information.

For the condition statement p \rightarrow q or equivalent "If p then q"

  • The rule for Converse is: Interchange the two statements.
  • The rule for Inverse is: Negative both statements.
  • The rule for Contrapositive is: Negative both statements and interchange them.

Part (A) If it snows tonight, then I will stay at home.

Here p is If it snows tonight, and q is I will stay at home.

Converse: If I will stay at home then it snows tonight.

q \rightarrow p

Inverse: If it doesn't snows tonight, then I will not stay at home.

\sim p \rightarrow \sim q

Contrapositive: If I will not stay at home then it doesn't snows tonight.

\sim q \rightarrow \sim p

Part (B) I go to the beach whenever it is a sunny summer day.

Here p is I go to the beach, and q is it is a sunny summer day.

Converse: It is a sunny summer day whenever I go to the beach.

q \rightarrow p

Inverse: I don't go to the beach whenever it is not a sunny summer day.

\sim p \rightarrow \sim q

Contrapositive: It is not a sunny summer day whenever I don't go to the beach.

\sim q \rightarrow \sim p

Part (C) When I stay up late, it is necessary that I sleep until noon.

P is I sleep until noon and q is I stay up late.

Converse: If I sleep until noon, then it is necessary that i stay up late.

q \rightarrow p

Inverse: When I don't stay up late, it is necessary that I don't sleep until noon.

\sim p \rightarrow \sim q

Contrapositive: If I don't sleep until noon, then it is not necessary that i stay up late.

\sim q \rightarrow \sim p

7 0
3 years ago
A ball is thrown into the air from the roof of a building that is 25
guapka [62]

See https://web2.0calc.com/questions/help_29603.

6 0
3 years ago
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