There are 60 seconds in one minute, and 60/5=12, so the race car would travel 100 feet every 5 seconds 12 times in one minute. You can simply multiply 100 by 12 to get your answer.
100x12=1200
The race car travels 1,200 feet in one minute.
Answer:
Class interval 10-19 20-29 30-39 40-49 50-59
cumulative frequency 10 24 41 48 50
cumulative relative frequency 0.2 0.48 0.82 0.96 1
Step-by-step explanation:
1.
We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.
Cumulative frequency
10
10+14=24
14+17=41
41+7=48
48+2=50
sum of frequencies is 50 so the relative frequency is f/50.
Relative frequency
10/50=0.2
14/50=0.28
17/50=0.34
7/50=0.14
2/50=0.04
Cumulative relative frequency
0.2
0.2+0.28=0.48
0.48+0.34=0.82
0.82+0.14=0.96
0.96+0.04=1
The cumulative relative frequency is calculated using relative frequency.
Relative frequency is calculated by dividing the respective frequency to the sum of frequency.
The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.
The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.
9514 1404 393
Answer:
8.6 km
Step-by-step explanation:
The circumference of a circle is given in terms of its radius as ...
C = 2πr
Then the radius can be found from the circumference using ...
r = C/(2π)
Filling in the given values, we find the radius to be ...
r = (54 km)/(2·2.14) = (54 km)/6.28 ≈ 8.59873 km
The radius is about 8.6 km.
