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3 years ago

If the following is a monomial, write it in standard form.

Mathematics

1 answer:

Sati [7]3 years ago

8 0

Answer:

Monomial; Standard form: 18a^2b^2

Step-by-step explanation:

$6 {a}^{2} 3 {b}^{2} = 6 \times 3 {a}^{2} {b}^{2} = 18{a}^{2} {b}^{2} \\$

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What is (0,-2) a solution of 2x-4y=-8

Paladinen [302]

Answer:

Step-by-step explanation:

4 0

2 years ago

What are the domain and range of this relation? 5 4 2 1 -5-4-3-2-10

marishachu [46]

The domain in a relation y(x) is the set of values for which the relation is defined (the values on x, where y is defined)

In this relation the values wich the relation is defined is: the coordinates of x where there are a point:

Domain: -1, 0, 3

The range in a relation y(x) is the set of all the values that y(x) takes (the values of y)

In this relation the values that takes y(x) are the coordinates of y where there are a point:

Range: -3, -1, 0

8 0

11 months ago

Please help logarithms!

nlexa [21]

Given:

$\log_34\approx 1.262$

$\log_37\approx 1.771$

To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

Solution:

We have,

$\log_34\approx 1.262$

$\log_37\approx 1.771$

Using properties of log, we get

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349$ $\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37$ $[\log x^n=n\log x]$

Substitute $\log_34\approx 1.262$ and $\log_37\approx 1.771$ .

$\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)$

$\log_3\left(\dfrac{4}{49}\right)=1.262-3.542$

$\log_3\left(\dfrac{4}{49}\right)=-2.28$

Therefore, the value of $\log_3\left(\dfrac{4}{49}\right)$ is $-2.28$ .

5 0

2 years ago

C is the midpoint of AD. B is the midpoint of AC. BC = 12. What is the length of AD

kvasek [131]

48 I would believe is the answer

6 0

3 years ago

Read 2 more answers

Ill start you out with a easy one 29999999 times 2333333333

Vadim26 [7]

Answer:

6.9999998e+16

Step-by-step explanation:

You literally just multiply

4 0

2 years ago