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sweet-ann [11.9K]
3 years ago
9

Cayden is 6 years older than Kaylee. If Cayden is y years old, and Kaylee is x years old, which of the following equations repre

sents the relationship between their ages?
Mathematics
2 answers:
masya89 [10]3 years ago
7 0

Answer: x + 6 = y OR y = x + 6 (same equation in different format)

Step-by-step explanation: If x represents Kaylee’s age, and Cayden is 6 years older, then you must always add 6 to Kaylee’s age in order to find Cayden’s age (y).

dlinn [17]3 years ago
6 0

Answer:

<em>x + 6 = y </em>or <em>y - 6 = x</em>

Step-by-step explanation:

If you know that Cayden is 6 years older than Kaylee, then <em>x</em> (Kaylee's age) + 6 years = <em>y</em> (Cayden's age). You don't know the ages of them but you still know how much older Cayden is than Kaylee.

It can also be <em>y </em>- 6 = <em>x</em> because it shows that if you subtract 6 years from Cayden's age, you get Kaylee's age.

I don't know the options to this question but I hope this helps you :)

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Which of the following is a multiple of 4?
Alex17521 [72]
2 × 2 is a multiple of 4 thats abould all you can do besides 4 × 1.
8 0
3 years ago
A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of
GenaCL600 [577]

Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 85 - 1 = 84

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.989.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

8 0
3 years ago
If you hike three miles every 5 minutes, how far are you going in 1 minute?
V125BC [204]

Answer:

0.6 miles per minute

Step-by-step explanation:

3/5 = 0.6/1 = 0.6

6 0
3 years ago
Read 2 more answers
Question 4
astraxan [27]

Answer:

No real roots

Step-by-step explanation:

The given equations are:

3x-1+2y=0

3x^2-y^2+4=0

We make y the subject in the first equation to get

y=\frac{1-3x}{2}

We substitute into the second expression to get:

3x^2-(\frac{1-3x}{2})^2+4=0

We expand to get:

3x^2-\frac{(1-6x+9x^2)}{4}+4=0

Multiply through by 4 to get:

12x^2-1+6x-9x^2+16=0

3x^2+6x+15=0

The discriminant is given by D=b^2-4ac

D=3^2-4*12*15

D=-711

Since the discriminant is less than zero, the two curves never intersects.

Therefore the system has no real roots

6 0
4 years ago
Can somebody help me?
dusya [7]
A) is the answer ( 3x-y)
3 0
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