Solutions
We know that <span>a spinner was divided into many different color sectors. Some sectors are larger than others. The spinner was spun 300 times. The results were tallied up and were written in a table.
</span><span>Red:93
Blue:59
Green:105
Yellow:43
</span>
The spinner landed the highest on green. To find <span>the probability that the next spin will land on green we have add all the numbers and simplify them.
93 + 59 + 105 + 43 = 300
Out of 300 the spinner landed to green 105 times. We have the fraction 105/300.
105/300 can be reduced. To reduce the fraction we need to the GCF of 105 and 300. The GCF is 15.
</span>We can reduce the fraction by dividing the numerator and denominator by the GCF = 15.
105 ÷ 15 = 7
300 ÷ 15 = 20
Our new fraction is 7/20
The <span>probability that the next spin will land on green is 7/20.
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To get the answer to part (B) we have to add the results of red and green then simplify.
93 + 105 = 198
The fraction is 198/300. </span><span>198/300 can be reduced. To reduce the fraction we need to the GCF of 105 and 300. The GCF is 6.
</span>We can reduce the fraction by dividing <span>the numerator and denominator by the GCF = 6.
</span>198 ÷ 6 = 33
300 ÷ 6 = 50<span>
The new fraction is 33/50
</span>The probability that the next spin will land on either green or red is <span>33/50.
</span>
Hope this helps
I hope this helps you
5+1/3v=8-4
6/3v=4
2/v=4
v=2/4
v=1/2
Answer:
it is 4/3
Step-by-step explanation:
because tan(B) = opposite/adjacent
K-2 I think I'm not sure though
