Given:
Consider the equation is:

To prove:
by using the properties of logarithms.
Solution:
We have,

Taking left hand side (LHS), we get

![\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_ab%3D%5Cdfrac%7B%5Clog_x%20a%7D%7B%5Clog_x%20b%7D%5Cright%5D)

![[\because \log x^n=n\log x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%20x%5En%3Dn%5Clog%20x%5D)

![\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_ab%3D%5Cdfrac%7B%5Clog_x%20a%7D%7B%5Clog_x%20b%7D%5Cright%5D)

Hence proved.
BRAINLIEST help pls,,,,,,,,,,,,,
icang [17]
Hey there!
1/3 = ?/12
If we observe denominator , it is multiplied by 4
So we must multiple numerator by 4 too
=> 1/3 x 4/4 = 4/12
? = 12.
Total number of seniors = 55 + 70 = 125
Number of seniors who plan to go to college = 55
Percentage of seniors who plan to go to college = 55/125 x 100 = 44%
Answer: 44%
Answer:
My guess would probably be $370.
Explanation:
The reason I say that is because since 200 euros was 270 American dollars, why not try the same thing for 300 euros? If you do the process of elimination, it wouldn't be the $540. The same for the second one so, you have 2 remaining options left. The third or the fourth.
Hope that helps!!
For number 1, it says based on the first two clues, so you would still include the even numbers ranging from 70-81. Then for number 2 we would use clue C because it gives us the most information about our number.