Answer:
A. 
by the SAS postulate.
Step-by-step explanation:
We have been two triangles. We are asked to determine the theorem by which both triangles could be proven congruent.
We can see that side DF of triangle DEF is equal to side AC of triangle ABC.
We can also see that side BC of triangle ABC is equal to side EF of triangle DEF.
The including angle between sides AC and BC of triangle ABC is equal to the including angle between sides DF and EF of triangle DEF.
Since both triangles have two sides and their included angles equal, therefore, triangle ABC is congruent to triangle DEF by SAS (Side-Angle-Side) congruence and option A is the correct choice.
20p + 9t = 44.4
Subtract 9t from both sides:
20p = 44.4 - 9t
Divide both sides by 20:
p = 2.22 - 0.45t
There will be 50 gift bags.
The first set of 25 bags
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Because there are 25 thumb drives, the first 25 bags will each have 1 thumb drive.
Also, each bag will have 5 times as many key chains as a thumb drive. Therefore each of the first 25 bags will have
1 thumb drive, 5 key chains.
After the first 25 bags, we have used
25 thumb drives, 5*25 = 125 key chains.
The second set of 25 bags
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We have a total of 200 key chains, so we have 200-125 = 75 key chains left.
Distribute them equally among the remaining 25 bags, so each bag has
75/25 = 3 key chains.
Answer:
25 bags, each with 1 thumb drive and 5 key chains.
Another 25 bags, each with 3 key chains.
Greater it is equal to 62.50
The answer is H= (1/2) b/A
