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lesya [120]
3 years ago
9

QUESTION 3

Chemistry
2 answers:
zhuklara [117]3 years ago
7 0

Answer:

the answer is C parasitism

insens350 [35]3 years ago
5 0
The answer is a.commensalism
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2) What is the concentration of NaCl in a solution prepared by diluting 56.98 ml of 0.5894 M stock
RSB [31]

Answer:

The NaCl concentration will be 0.03 M.

Explanation:

Given data:

Initial volume = V₁ = 56.98 mL (56.98/1000 = 0.05698 L)

Initial concentration = M₁= 0.5894 M

Final volume = V₂= 1.20 L

Final concentration = M₂= ?

Solution:

By diluting the solution volume of solution will increase while number of moles of solute remain the same.

Formula:

Initial concentration × Initial volume  = Final concentration × Final volume

M₁V₁ = M₂V₂

M₂ = M₁V₁ / V₂

M₂ = 0.5894 M × 0.05698 L / 1.20 L

M₂ = 0.0336 M /1.20  

M₂ = 0.03 M

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How will the vapor pressure of an aqueous solution of sodium chloride compare to that of pure water?
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The vapor pressure of a compound refers to the pressure generated by the vapour of a compound in equilibrium with its condensed stage. The major determinant of a compound vapour pressure is temperature. The vapour pressure of an aqueous solution of sodium chloride will be lower than that of pure water. This is because, dissolution of solute in a solvent always reduces the vapour pressure of the solution as a result of interactions between the molecule of the solute and the solvent. Thus, a pure compound will always have a higher vapour pressure than a solution.

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