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Alex
2 years ago
10

Please help if you want brianleist!! :) uhm don't mind update- NO LINkS child.. Ty!

Mathematics
1 answer:
Vinil7 [7]2 years ago
4 0

Answer: 5 or c

Step-by-step explanation:

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At the beginning of the week the balance in your checkbook was $298.72. During the week you made a deposit of $425.69. You also
Furkat [3]

Hello!

Throughout this problem, we will add or subtract values from our original balance.

In your checkbook, there was 298.72 dollars, and then you deposited 425.69 dollars. The function you would do is addition.

$298.72 + 425.69 = $724.41

If you wrote a check, then the amount you wrote is removed from your checkbook.

$724.41 - $29.72 - $135.47- $208.28 = $350.94

Then, the bank deducted 5 dollars from your account.

$350.94 - $5.00 = $345.94

This leaves you with $345.94 at the end of the week.

Therefore, your answer is choice C, $345.94.

4 0
2 years ago
Read 2 more answers
Mr smiths loan balance has decreased by 71.4%. Calculate the change in his loan balance
nikklg [1K]
Can you write the full question
4 0
3 years ago
On a blueprint the length of a wall is 5 centimeters. If the actual length of the wall is 15 feet, what is scale of the blueprin
Ludmilka [50]

Answer:

The wall is 90 meters wide.

Step-by-step explanation:

1. set up and solve a proportion to find the value of w like this:

1cm=6cm

15m=wm

2. cancel out the like units on both sides of the equation

1=6

15=w

3. Equate the cross products, and then solve for w:

1*w=15*6

w=90                                                                                                                                          The actual width of the wall is 90 meters.

5 0
3 years ago
6. Explain why <1 = <2.
slavikrds [6]

Step-by-step explanation:

Since AC=BE & DE=DC

then measure angle <CAD=<EBD =X

Then< DAB =90-x

And <ABD= 90-X

then measure angle 1= measure angle 2

8 0
2 years ago
Calculate the second moment of area of a 4-in-diameter shaft about the x-x and yy axes, as shown.
Keith_Richards [23]
Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.

The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.

6 0
3 years ago
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