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Eva8 [605]
3 years ago
7

Calculate the number of moles of NaOH that are needed to react with 500.0 g of

Chemistry
1 answer:
Alenkasestr [34]3 years ago
7 0

Answer:

2.55 moles of NaOH are needed react with 500.0 gram of H₂SO₄.

Explanation:

Given data:

Mass of H₂SO₄ = 500.0 g

Number of moles of NaOH needed = ?

Solution:

H₂SO₄ + 2NaOH  → Na₂SO₄ + 2H₂O

Number of moles of H₂SO₄:

Number of moles = mass/molar mass

Number of moles = 500.0 g/ 98.07 g/mol

Number of moles = 5.09 mol

Now we will compare the moles of H₂SO₄ and NaOH.

                     H₂SO₄         :           NaOH

                           1             :               2

                         5.09         :            1/2×5.09 = 2.55 mol

Thus, 2.55 moles of NaOH are needed react with 500.0 gram of H₂SO₄.

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Help me pleaseee. ty if you dooo :))
Lina20 [59]

\huge \fcolorbox{black}{red}{♛answer♛}

Hydrogen Fluoride / HF

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3 0
2 years ago
Radioactive decay can be described by the following equation where is the original amount of the substance, is the amount of the
soldi70 [24.7K]

Answer:

Iron remains = 17.49 mg

Explanation:

Half life of iron -55 = 2.737 years (Source)

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{2.737}\ year^{-1}

The rate constant, k = 0.2533 year⁻¹

Time = 2.41 years

[A_0] = 32.2 mg

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

So,  

[A_t]=32.2\times e^{-0.2533\times 2.41}\ mg

[A_t]=32.2\times e^{-0.610453}\ mg

[A_t]=17.49\ mg

<u>Iron remains = 17.49 mg</u>

8 0
3 years ago
What can group numbers on the periodic table help you determine?
Ilia_Sergeevich [38]
Http://www.chem4kids.com/files/elem_pertable.html this should help.
4 0
3 years ago
How do electrons populate atoms?
lutik1710 [3]
Electrons fill the electron orbitals (s, p, d, or f) starting from the lowest energy level going to the highest energy level. I hope this helps. let me know if you need more information such as what the
7 0
3 years ago
The density of an unknown gas is 4. 20 grams per liter at 3. 00 atmospheres pressure and 127 °c. what is the molecular weight of
Kryger [21]

The molecular weight of this gas will be 45 g/mol .

The state equilibrium equation for a fictitious perfect gas is known as the ideal gas law, sometimes known as the generic gas equation. Although it has significant drawbacks, it represents a decent approximation of the activity of many gases under various conditions.

Ideal gas law can be expressed as:

PV =nRT

Calculation of molecular weight by using ideal as law.

Given data:

P = 3 atm

T = 127 °c

Density =  4. 20 grams per liter

PV =nRT

where p is pressure , T is temperature and R is gas constant.

PV = gram / molecular weight RT

Molecular weight = (g/v)( 1/P) RT

Putting the given data in above equation.

Molecular weight =4.20 × 1/ 3× 400 × 0.0831

Molecular weight = 45 g/mol.

To know more about Molecular weight

brainly.com/question/27988184

#SPJ4

4 0
2 years ago
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