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ddd [48]
3 years ago
8

A silver block, initially at 59.4 °C, is submerged into 100.0 g of water at 24.8 °C, in an insulated container. The final temper

ature of the mixture upon reaching thermal equilibrium is 26.2 °C.
What is the mass of the silver block?
Chemistry
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

The mass of silver block = 73.95 g

Explanation:

Given,

For water:

Mass = 100.0 g

Initial temperature = 24.8 °C

Final temperature = 26.2 °C

Specific heat of water = 4.184 J/g°C

For silver:

Mass = x g

Initial temperature = 59.4 °C

Final temperature = 26.2 °C

Specific heat of water = 0.2386 J/g°C

Heat gain by water = Heat lost by silver

Thus,  

m_{water}\times C_{water}\times (T_f-T_i)=-m_{silver}\times C_{silver}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

m_{water}\times C_{water}\times (T_f-T_i)=m_{silver}\times C_{silver}\times (T_i-T_f)

So,  100.0\times 4.184\times (26.2-24.8)=x\times 0.2386\times (59.4-26.2)

x\times \:0.2386\left(59.4-26.2\right)=100\times \:4.184\left(26.2-24.8\right)

x\times \:0.2386\left(59.4-26.2\right)=585.76

x=\frac{585.76}{7.92152}

x=73.95

<u>Hence, the mass of silver block = 73.95 g</u>

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The yearly amounts of carbon emissions from cars in Belgium are normally distributed with a mean of 13.9 gigagrams per year and
zavuch27 [327]

Answer:

The correct option is;

c. 0.167

Explanation:

The parameters given are;

The mean, μ = 13.9 Gigagrams/year

The standard deviation, σ = 5.8 Gigagrams/year

The z-score formula is given as follows;

z = \dfrac{x - \mu }{\sigma }

Where:

x = Observed score = 11.5 Gigagrams/year

We have;

z = \dfrac{11.5 - 13.9 }{5.8 } =  \dfrac{-2.4 }{5.8 } = 0.4138

From the z-score table relations/computation, the probability (p-value) = 0.6605

Where:

x = Observed score = 14 Gigagrams/year

We have;

z = \dfrac{14- 13.9 }{5.8 } =  \dfrac{0.1}{5.8 } = 0.01724

From the z-score table relations/computation, the probability (p-value) = 0.4931

Therefore, the probability, p_{ca}, that the amount of carbon emissions from cars in Belgium for a randomly selected year are between 15.5 Gigagrams/year and 14 Gigagrams/year = The area under the normal curve bounded by the p-values for the two amounts of carbon emission

Which gives;

p_{ca} = 0.6605 - 0.4931 = 0.1674 ≈ 0.167

Therefore, the correct option is c. 0.167.

4 0
3 years ago
If 20.0g of MgSO4⋅7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?
alina1380 [7]

Answer: 9.8g

Explanation:

The calculation is based on the fact that all the water in the molecule will be removed.

i will, then, calculate the mass of water removed and then subtract it from the original 20.0 g of sample.

You can do that following these steps.

1) Calculate the number of moles of the hydrated magnsium sulfate, MgSO₄⋅7H₂O

number of moles = mass in grams / molar mass

The molar mass of MgSO₄⋅7H₂O is calcualted from the atomic mass of each atom times the number of atoms in the formula:

molar mass = 24.305 g/mol + 32.065 g/mol + 4×15.999g/mol + 7×2×1.008g/mol + 7×15.999 g/mol = 246.471 g/mol

⇒ moles of MgSO₄⋅7H₂O = 20.0g / 246.471 g/mol = 0.0811 moles

2) Calculate the number of moles of water, using the ratio from the chemical formula:

7 moles H₂O / 1 mol MgSO₄⋅7H₂O = x / 0.0811 mols MgSO₄⋅7H₂O

⇒ x = 0.0811 × 7 moles H₂O = 0.568 moles H₂O

3) Convert moles of H₂O to grams:

number of moles = mass in grams × molar mass = 0.568 moles × 18.015 g/mol = 10.2 g

4) Hence the mass remaining is 20.0g - 10.2g = 9.8g

5 0
3 years ago
Read 2 more answers
Balance this equation. If a coefficient of "1" is required, choose "blank" for that box.
Andrej [43]
When balancing  the  equation  you  need  to  know  how  many     moles  reacted  and  how  many were formed.To  balance  this  equation  we  require  1 moles  of  C2H4,  3moles  of  O2  to  form 2  moles CO2  and 2 moles  H2o
therefore the  equation is  represented  as
 C2H4+3O2 ->2CO2+2H2O
4 0
2 years ago
Read 2 more answers
A sample of a monoprotic acid (ha) weighing 0.384 g is dissolved in water and the solution is titrated with aqueous naoh. if 30.
posledela
The formula for the monoprotic acid is taken as HA, reaction with base is as follows;
HA + NaOH ---> NaA + H₂O
Stoichiometry of acid to base is 1:1
At the neutralisation point, number of HA moles = number of base moles
Number of NaOH moles reacted = 0.100M / 1000 mL /L x 30.0 mL = 0.003 mol
Therefore number of HA moles reacted = 0.003 mol
the mass of acid 0.384 g
Therefore molar mass - 0.384 g/ 0.003 mol = 128 g/mol
3 0
2 years ago
if a gas has an initial pressure of 24,650 pa and an initial volume of 376 ml, what is the final volume if the pressure of the g
NNADVOKAT [17]

If a gas has an initial pressure of 24,650 pa and an initial volume of 376 ml, then the final volume would be 11,943.8144 ml if the pressure of the gas is changed to 775 torr assuming that the amount and the temperature of the gas remain constant.

It is given that the initial pressure P₁ is 24,650Pa and initial volumeV₁ is 376ml and the final pressureP₂ is 775 torr. We need to find the final volume of the gas. The final volume could be found using the following formula:

P₁V₁ = P₂V₂

By substituting the values, we get

24650 x 376 = 776 x V₂

9268400 = 776V₂

V₂ = 9268400/776

V₂ = 11,943.8144 ml

Therefore, the final volume of the gas would be 11,943.8144 ml

To know more about Partial pressure, click below:

brainly.com/question/14119417

#SPJ4

5 0
8 months ago
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