A line passes through the point (4, –2) and has a slope of One-half.

A surveyor has poles A, B, and C set to form a right triangle with the right angle at B. If the distance from A to B is 35 meter

tia_tia [17]

A^2+b^2=c^2
35^2+25^2=25^2
So the answer is 25

6 0

3 years ago

A 32-ounce package of a snack mix is 24 percent pretzels. How many ounces are pretzels?

xz_007 [3.2K]

Answer: The correct answer is Choice D.

If 24 percent of the snack mix is pretzel, we simply need to multiply the total number of ounces by 0.24.

0.24 x 32 = 7.68

7.68 ounces of the snack mix will be pretzels.

8 0

3 years ago

Read 2 more answers

Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

4 0

3 years ago

At 5:00pm the temperature read 10° above zero. At midnight it read 4 ° below zero. Find the change

larisa86 [58]

The temperature changed a total of 14° over the course of 7 hours with an average change of 2° per hour drop.

6 0

2 years ago

I need the percentage of the shaded area.

arsen [322]

Answer:

1.22

Step-by-step explanation:

Since there is one whole shaded. And 2 tens, and 2 ones. Its 1.22.

3 0

2 years ago