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levacccp [35]
3 years ago
5

A line passes through the point (4, –2) and has a slope of One-half.

Mathematics
1 answer:
dalvyx [7]3 years ago
6 0

Answer:

-6

Step-by-step explanation:

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A line segment is formed by connecting two points located at (-4,2) and (2,-1). What is the slope of this line segment? A.-3/8 B
Scorpion4ik [409]
The formula for slope is 
m= (y₂-y₁)/(x₂-x₁)
you can plug in the points that you are given to find the slope
m= (-1-2)/(2-(-4)
m= -3/6

the slope is -3/6 which reduced to -1/2

so the answer would be 
c) -1/2

hope this helped!
3 0
3 years ago
A line passes through the points (–5, 2) and (10, –1). Which is the equation of the line?
beks73 [17]

Slope = (2 + 1) / (-5 - 10) = -3/15 = - 1/5

Equation

y - 2 = -1/5 (x + 5)

y - 2 = -1/5 x - 1

y = -1/5 x + 1

Answer

y = -1/5 x + 1

6 0
4 years ago
Read 2 more answers
On a road trip, london and his friends see 10 cities over 5 days. How many cities Landon and his friends will see in 8 days? Sol
Svetlanka [38]

Answer:

16 cities

Step-by-step explanation:

if 5days = 10 cities

8days=?

applying cross multiplication :

(8days × ten cities )÷5 day

= 16 cities

6 0
3 years ago
Write two multiplication problems that have the same product 3 × 2/6
Ulleksa [173]
4×2/8
5×2/10
6×2/12
7×2/14
8×2/16
9×2/18
10×2/20
There are a lot more problems but here are a couple to help you for now.
8 0
3 years ago
I roll a fair die twice and obtain two numbers X1= result of the first roll and X2= result of the second roll. Given that I know
azamat

By definition of conditional probability,

P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{P((X_1=4\text{ or }X_2=4)\text{ and }X_1+X_2=7)}{P(X_1+X_2=7)}

=\dfrac{P((X_1=4\text{ and }X_1+X_2=7)\text{ or }(X_2=4\text{ and }X_1+X_2=7))}{P(X_1+X_2=7)}

Assuming a standard 6-sided fair die,

  • if X_1=4, then X_1+X_2=7 means X_2=3; otherwise,
  • if X_2=4, then X_1=3.

Both outcomes are mutually exclusive with probability \frac1{36} each, hence total probability \frac2{36}=\frac1{18}.

Of the 36 possible outcomes, there are 6 ways to sum the integers 1-6 to get 7:

(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)

and so a sum of 7 occurs \frac6{36}=\frac16 of the time.

Then the probability we want is

P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{\frac1{18}}{\frac16}=\frac13

6 0
3 years ago
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