Hello!
We have two probabilities we can use; we have 170/400, for our experiment, and 1/2, which is our theoretical probability.
To solve, we just multiply the two probabilities.
=0.2125≈21.3
Therefore, we have about a 21.3% chance of this event occurring.
I hope this helps!
use one five dollar box then use 4 4 $ boxes then its five dollar boxes the rest of the way so it would be 59 5$ boxes then Four 4$ boxes
Perimeter of rectangle:
P = 2(L + W)
P = 250 (given)
L = 3W - 35 (given)
250 = 2(3W -35 + W) ↔ 125 = 4W - 35
4W = 125 +35 =160 And W = 40 ft
And L = 3x40 - 35 = 85 ft
A) The total number is the sum of all the frequencies
2+5+8+12+11+6=44
Answer: 44
B) The width is (upper limit - lower limit) / 2
(35-21) / 2 = 7
(50-36) / 2 = 7
(65-51) / 2 = 7
(80-66) / 2 = 7
(95-81) / 2 = 7
(110-96) / 2 = 7
Answer: the width is 7
C) The midpoint is the lower limit + the width
36+7=43
Answer: the midpoint is 43
D)The modal is the class with more frequency
In this case 66-80 with 12
Answer: class 66-80
E) We use the width formula
lower limit = 111
width = 7
upper = (width * 2) - lower
upper = (7 * 2) + 111
upper = 125
Answer: class 111-125
Answer:
(x+y ) (x+8)
Step-by-step explanation:
x² + xy+8x+8y
grouping like terms
x² + 8x +xy+8y
x(x+8) + y(x+8)
>> (x+y)(x+8)
