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2 years ago

Multiply 2.3. (-1.2)

Mathematics

1 answer:

JulsSmile [24]2 years ago

4 0

Answer:

-2.76

Step-by-step explanation:

2.3x(-1.2)

= -2.76

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Solve for h.<br><br> –2 − 10h = –11h − 20

Delvig [45]

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-2 - 10h = -11h - 20

+ 2

- 10h = -11h - 18

+ 11h

h = -18

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3 years ago

Twelve more then the product of 5 and a number x? x is 2

yaroslaw [1]

Answer:

Step-by-step explanation:

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3 years ago

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

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3 years ago

What is 875x132 written out in long multiplication

lukranit [14]

857 x 132= 113,124
work is showed in the image

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3 years ago

Multiply 2.3. (-1.2)​

Multiply 2.3. (-1.2)