The two equations would be

32a+50b=14600
10a+40b=7000
To solve, we need to eliminate one variable.... let’s eliminate b

4(32a+50b=14600) —> 128a+200b=58400
-5(10a+40b=7000) —> -50a-200b=-35000
So when we add them together’ we get 78a = 23400
So solve that and a= 300, so class a tickets cost 300 euros each

Substitute a=300 into first equation in the system of equations at the beginning and 32(300)+50b=14600 —> 9600+50b=14600 —> 50b = 5000 or b= 100, so the cost for class b tickets is 100 euros each

7 0

3 years ago

you are starting your own buisness making candles. You spent $350 to get started and will charge each customer $85 for a case of

lara31 [8.8K]

Answer:

Option c.

Step-by-step explanation:

Missing options are attached below.

Given: Initial Investment is $350

Selling price for each case of candles is $85.

Lets assume the number of case of candles be "x".

And let profit be "p".

The intitial investment will be negative as there is no immediate earning on it.

∴ Initial investment= -350

Profit increase with the number of customer buy the case of candles.

We know, $Profit= selling\ price - Cost\ price$

Here, cost is the amount spent in starting the business.

Now, $p= 85x-350$

Therefore, as per equation y intercept is -350 and slope is 85.

If divide the initial investment by selling price of each case of candles, we will get number of case of candle need to bought to get break even point of business, which is $Cost Price - Selling Price= 0$