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3 years ago

PLEASE HELP!! I NEED MATHEMATICIANS ON THIS POST!!

Mathematics

1 answer:

aalyn [17]3 years ago

7 0

Answer:

60 * 40% = 24

Step-by-step explanation:

just use a calculator

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4. In the expression -9x-2 +7, what is the coeffcent of x?<br> A.-9<br> B.-2<br> C.7<br> D.9

12345 [234]

A coefficient is the number before the variable so the coefficient of x would be number before the x. the number before x is A.-9

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3 years ago

Name the property of equality that justifies the statement: rs = rs

harkovskaia [24]

A. reflexive property
hope it helps.

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3 years ago

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One hundred twenty feet of fencing encloses a rectangular garden on three sides. One side of the garden is the side of a barn an

andre [41]

Answer: The garden has dimensions 30 ft wide X 60 ft long

Step-by-step explanation:

Denote by W the width of the garden and L the length of the garden (longer side) as in the figure attached. The red sides on the figure represent the parts of the garden that require fencing.

L is also the measure of a vertical side of the garden, because a rectangle consists only of vertical and horizontal sides.

We know that the barn is parallel to the longer (vertical) side, so only one of the vertical sides L of the rectangle needs fencing. The other two parts correspond to the horizontal sides of the rectangle so they require 2W feet of fencing. Altogether, the 120 ft of fencing enclose the L+2W ft of the fence, then 120=L+2W. Because the longer side is twice the width, we have that L=2W, so 120=2W+2W=4W. From here, W=30 ft and L=2(30)= 60ft.

5 0

3 years ago

I need the function for the volume of the box for number 1

rjkz [21]

Answer:

Step-by-step explanation:

The volume of a rectanguiar shape like this one is V = L * W * H, where the letters represent Length, Width and Height. Here L is the longest dimension and is 28 - 2x; W is the width and is 22-2x; and finally, x is the height. Thus, the volume of this box must be

V(x) = (28 - 2x)*(22 - 2x)*x

and we want to maximize V(x).

One way of doing that is to graph V(x) and look for any local maximum of the graph. We'd want to determine the value of x for which V(x) is a maximum.

Another way, for those who know some calculus, is to use the first and second derivatives to identify the value of x at which V is at a maximum.

I have provided the function that you requested. If you'd like for us to go all the way to a solution, please repost your question.

3 0

2 years ago

If an open box has a square base and a volume of 115 in.3 and is constructed from a tin sheet, find the dimensions of the box, a

Karolina [17]

Let h = height of the box,
x = side length of the base.

Volume of the box is $V=x^{2} h = 115$ .
So $h = \frac{115}{ x^{2} }$

Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is
$S = 2( x^{2} + hx + hx) \\ = 2 x^{2} + 4hx \\ = 2 x^{2} + 4( \frac{115}{ x^{2} } )x$
$= 2 x^{2} + \frac{460}{x}$
The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.

$S' = 4x- \frac{460}{ x^{2} } = 0$
$4x = \frac{460}{ x^{2} } \\ 4x^{3} = 460 \\ x^{3} = 115 \\ x = \sqrt[3]{115} = 4.86$
Then $h= \frac{115}{4.86^{2}} = 4.87$
So the box is 4.86 in. wide and 4.87 in. high.

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3 years ago

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