An airline has a policy of booking as many as 15 persons on an airplane that can seat only 14. (Past studies have revealed that
1 answer:
Answer: No, it is unlikely for such an overbooking to occur.
Our required probability is 0.146.
Step-by-step explanation:
Since we have given that
Number of persons on an airplane book = 15
Probability of booked passengers actually arrive for the flight = 88%
We need to find the probability that if the airline books 15 persons, not enough seats will be available.
We will use "Binomial distribution":
Probability would be
No, it is unlikely for such an overbooking to occur.
Hence, our required probability is 0.146.
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Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
