All categories

3 years ago

Can anyone help me do this

Mathematics

2 answers:

charle [14.2K]3 years ago

7 0

Step-by-step explanation:

Let the unknown number be x

it means 46089-X should give you the number 3479, since the question could be interpreted as "by how much should you reduce 46089 to get 3479

As a result, 46089 - X = 3479

collecting like terms, X = 46089 - 3479

hence, X = 42610

therefore, the number is 42610

hope this was helpful?...

SVETLANKA909090 [29]3 years ago

4 0

Answer:

b) 42,610

Step-by-step explanation:

46089 - 3479 = 42610

You might be interested in

I will give brainliest

alina1380 [7]

Answer:

3532.5

Step-by-step explanation:

The formula for the volume of a cylinder is 3.14 times R^2 times H

I calculated it

5 0

3 years ago

A study conducted in 2000 found that the mean number of children under 18 per household in a certain community was 1.7. A statis

Margarita [4]

Answer:

c). Two tailed test

Step-by-step explanation:

The given hypothesis are

Null hypothesis: H0:μ= 1.7

Alternative hypothesis: H1:μ≠ 1.7

The alternative hypothesis demonstrates that mean number of children are not 1.7 in 2000. This means that mean number of children can be greater than 1.7 or mean number of children can be less than 1.7. Thus, the given alternative hypothesis indicates the two tailed test.

3 0

3 years ago

PLS HELP I WILL GIVE 15 POINTS OR MORE PLS NO SPAMMING PLS

Blizzard [7]

B,D,F / I’m pretty sure I did this not to long ago

3 0

3 years ago

Read 2 more answers

Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. (a) Descr

Daniel [21]

Answer:

(a) The sampling distribution of $\overline{X}$ = Population mean = 79

(b) P ( $\overline{X}$ greater than 81.2 ) = 0.1357

(c) P ( $\overline{X}$ less than or equals 74.4 ) = .0107

(d) P (77.6 less than $\overline{X}$ less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean $(\nu)$ = 79

Standard deviation $(\sigma )$ = 18

(a) Describe the sampling distribution of $\overline{X}$

For large sample using central limit theorem

the sampling distribution of $\overline{X}$ = Population mean = 79

(b) What is Upper P ( $\overline{X}$ greater than 81.2 ) =

$P(\overline{X}> 81.2)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})$

= $P(Z> 1.1)$

= $1 - P(Z< 1.1)$

= 1 - .8643 =

= 0.1357

$P(\overline{X}\leq 74.4)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{74.4- 79}{\frac{18}{\sqrt{81}}})$

= $P(Z\leq -2.3)$

= .0107

(d) What is Upper P (77.6 less than $\overline{X}$ less than 83.2 ) =

$P(77.6< \overline{X}< 83.2)$ = $P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{83.2- 79}{\frac{18}{\sqrt{81}}})$