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Wittaler [7]
2 years ago
13

7: (page 311) Triangle DEF has vertices D(1,2), E(1,6), and F(4,2). What are the coordinates of

Mathematics
1 answer:
jekas [21]2 years ago
3 0

Answer:

u

Step-by-step explanation:

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If anyone could please help me with this question???I know that you can get three triangles out of the shape.
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Answer:

See below.

Step-by-step explanation:

The triangles are similar because  the angles marked 125 are equal and the sides either side of these angle are in the same ratio:

1.3 / 2.5 = 2.6 /5.

If we are given the length of AE we would find CF from the equation:

1.3 / 2.5 = CF / AE

CF = (1.3 * AE) / 2.5.

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3 years ago
Enter numbers into the table so that the paired values are in a proportional relationship. In each slot, which numbers would go
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i think y is 1 x = 12

Step-by-step explanation:


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2 years ago
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How many terms will the given expression have once it is simplified?
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8x^2-8+3x^2+6x
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25,000 bricks were used to build the new library. The total weight of the bricks was 30,000 pounds. What is the weight of each b
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7 0
3 years ago
In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Liberal Arts Co
sukhopar [10]

Answer:

a. proportions have not changed significantly

Step-by-step explanation:

Given

Business College= 35 %

Arts College= 35 %

Education College = 30%

Calculated

Business College = 90/300= 9/30= 0.3 or 30%

Arts College= 120/300= 12/30= 2/5= 0.4 or 40%

Education College= 90/300= 9/30 = 0.3 or 30%

First we find the mean and variance of the three colleges using the formulas :

Mean = np

Standard Deviation= s= \sqrt{npq\\}

Business College

Mean = np =300*0.3= 90

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.3*0.7*300}= 7.94

Arts College

Mean = np =300*0.4= 120

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.4*0.6*300}=  8.49

Education College

Mean = np =300*0.3= 90

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.3*0.7*300}= 7.94

Now calculating the previous means with the same number of students

Business College

Mean = np =300*0.35= 105

Arts College

Mean = np =300*0.35= 105

Education College:

Mean = np =300*0.3= 90

Now formulate the null and alternative hypothesis

Business College

90≤ Mean≥105

Arts College

105 ≤ Mean≥ 120

Education College

U0 : mean= 90     U1: mean ≠ 90

From these we conclude that the  proportions have not changed significantly meaning that it falls outside the critical region.

8 0
3 years ago
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