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vladimir2022 [97]
3 years ago
11

4 + -5 * -1 + 8=? i need help so yeah

Mathematics
2 answers:
Natasha2012 [34]3 years ago
8 0

Answer:

1

Step-by-step explanation:

4+(-5*-1)-8

4+5-8

9-8

pemdas

olga_2 [115]3 years ago
5 0

Answer:

4 easy

Step-by-step explanation:

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What is 35+[16-7+(3+5)]
Nadya [2.5K]

Answer:

52

Step-by-step explanation:

1) Simplify the inner most parentheses:

35 + [16 - 7 + 8}

2) Perform the operations inside the brackets:

35 + [17]

3) Add

52

7 0
3 years ago
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A screening test for a disease shows a positive result in 91% of all cases when the disease is actually present and in 7% of all
Jobisdone [24]

Answer:

0.0713 = 7.13% probability that the result is positive.

Step-by-step explanation:

Probability of a positive test:

91% of 1/650(has the disease).

7% of 1 - 1/650 = 649/650(does not have the disease). So

p = 0.91\frac{1}{650} + 0.07\frac{649}{650} = \frac{0.91 + 0.07*649}{650} = 0.0713

0.0713 = 7.13% probability that the result is positive.

4 0
2 years ago
A flowchart can be a(n)<br> O Hamilton circuit<br> Euler les<br> tree graph
Fiesta28 [93]

Answer:

I need points sry plz dont dellete

Step-by-step explanation:

6 0
3 years ago
A man invest 5,200,part at 4% and the balance at 3%. If his total income for the two investments is $194,how much money did he i
Fed [463]

Let the amount invested at 4% be = x

Let the amount invested at 3% be = y

Given is:

x+y=5200 or x=5200-y  .... (1)

As, total income for the two investments is $194, so equation is:

0.04x+0.03y=194   ....(2)

Putting value of x from (1) in (2)

0.04(5200-y)+0.03y=194

208-0.04y+0.03y=194

0.01y=14

y=1400

And x=5200-y

x=5200-1400=3800

Hence, money invested at 4% is $3800 and money invested at 3% is $1400

6 0
3 years ago
A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d
Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

P(A) = P_{1} + P_{2} + P_{3}

In which P_{1} is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

P_{1} = 0.35*0.25 = 0.0875

P_{2} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{2} = 0.15*0.05 = 0.0075

P_{3} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{3} = 0.50*0.15 = 0.075

So

P(A) = 0.0875 + 0.0075 + 0.075 = 0.17

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

P = \frac{0.5*0.15}{0.17} = 0.4412

There is a 44.12% probability that the defective product came from C.

3 0
3 years ago
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