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Umnica [9.8K]
2 years ago
9

If Carly has 3 apples and she eats 2 of them how many apples does she have left

Mathematics
2 answers:
Sonbull [250]2 years ago
5 0

Answer:

SHE HAS ONLY HAS 1 LEFT

Step-by-step explanation:

3 - 2 = 1

Alex_Xolod [135]2 years ago
3 0
Carly will have one apple left, (3-2=1)
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Determine whether the improper integral converges or diverges, and find the value of each that converges.
Temka [501]

Answer:

It diverges.

Step-by-step explanation:

We are given the inetegral:  \int\limits^{\infty}_2 \frac{1}{x} (\ln x)^2 dx

\int\limits^{\infty}_2 \frac{1}{x} (\ln x)^2 dx=\int\limits^{\infty}_2 (\ln x)^2 d(\ln x)=\\\\=\lim_{t \to \infty} \int\limits^t_2 (\ln x)^2d(\ln x)=\lim_{t \to \infty} \frac{(\ln t)^3}{3} |^t_2=\infty-\frac{(\ln 2)^3}{3} =\infty

So it is divergent.

7 0
3 years ago
What is the slope- intercept form equation of the line that passes through (5, 7) and (8, 22)
kap26 [50]
M = (22 - 7)/(8 - 5) = 15/3 = 5 
<span>using point (5, 7) </span>
<span>y - 7 = 5(x - 5) in point-slope form </span>
<span>y - 7 = 5x - 25 </span>
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3 0
3 years ago
Answer choices<br> A. 23<br> B. 25<br> C. 35<br> D. 50
Tasya [4]
35? I’m not sure what the question is asking
3 0
3 years ago
Read 2 more answers
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
3 years ago
Read 2 more answers
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garri49 [273]
THE PROBABILITY IS likely to be one half half of the slice of the pizza
7 0
3 years ago
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