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julia-pushkina [17]

3 years ago

15

Help please!!! I will give a gold medal.

1 answer:

morpeh [17]3 years ago

8 0

Well assuming that this would be a typical triangle, and not a right angle one, knowing that the sum of all sides adds up to 180 degrees, simply add all of the expressions and one value and make it equal to 180, and then solve for x.

(6x-1) + (X+14) + 20 = 180
6x - 1 + X + 14 = 160
7x - 1 + 14 = 160
7x + 13 = 160
7x = 147
X = 21.

Now solve for the angles by plugging in X.

A = 6x - 1 = 6(21) - 1 = 125 degrees
C = X + 14 = (21) + 14 = 35 degrees.

I believe these are the solutions.

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I do not understand this. Can you please explain.

klemol [59]

Answer:

E

Step-by-step explanation

y^(3/5) = $\sqrt[5]{y{3}}$

y^(-3/5) = 1/ $\sqrt[5]{y{3}}$

3 0

2 years ago

PLEASE HELP AND SHOW YOUR WORK!!

trasher [3.6K]

Answer: The answer would be B) 9% Decrease!

275 - 250 = 25.

25/275 = 0.0909090909

0.0909090909 x 100 = 9.09090909091

Finally you'd round it to 9%.

Therefore there was a 9% decrease in the amount of large pizzas.

Hope this helps (: Stay safe.

8 0

3 years ago

Read 2 more answers

A square blanket has a diagonal stripe. The diagonal stripe is 66 inches long. How long is each side of the square blanket?

user100 [1]

9514 1404 393

Answer:

33√2 in ≈ 46.7 inches

Step-by-step explanation:

The diagonal of a square is √2 times the side length, so for side length s we have ...

s√2 = 66 in

s = (66 in)/√2

x = 33√2 in ≈ 46.7 in . . . . length of each side of the blanket

6 0

2 years ago

NO LINKS!!! Please help find the match

Mkey [24]

Answer:

HI = 8

TU = 45

Step-by-step explanation:

→ Find the scale factor enlargement

45 ÷ 10 = 4.5

→ Multiply JI by the scale factor to find it

10 × 4.5 = 45

→ Divide UV by the scale factor to find it

36 ÷ 4.5 = 8

3 0

1 year ago

Read 2 more answers

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by: P(x)=-12x^2 +12

Minchanka [31]

Given:

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by:

$P(x)=-12x^2+120x$

To find:

The current that will produce the maximum power.

Solution:

We have,

$P(x)=-12x^2+120x$

Here, leading coefficient is negative. So, it is a downward parabola.

Vertex of a downward parabola is the point of maxima.

If a parabola is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

In the given function, a=-12 and b=120. So,

$-\dfrac{b}{2a}=-\dfrac{120}{2(-12)}$

$-\dfrac{b}{2a}=-\dfrac{120}{-24}$

$-\dfrac{b}{2a}=5$

Putting x=5 in the given function, we get

$P(5)=-12(5)^2+120(5)$

$P(5)=-12(25)+600$

$P(5)=-300+600$

$P(5)=300$

Therefore, 5 watt current will produce the maximum power of 300 amperes.

6 0

2 years ago