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Lapatulllka [165]
3 years ago
15

Given that

Mathematics
1 answer:
marishachu [46]3 years ago
7 0

<h2><u>Given</u><u>:</u><u>-</u></h2>
  • p=10x+2y
  • x=4
  • y=6

<h2><u>To</u><u> </u><u>find</u><u>:</u><u>-</u></h2>
  • value of p.

<h2><em><u>Solution</u></em><em><u>:</u></em>-</h2>

\mapsto\bold{p=10x+2y   } 

\mapsto\bold{p=10\times 4+2y~(\because{x=4})   } 

\mapsto\bold{p=10\times 4+2\times 6~(\because{y=6})   } 

\mapsto\bold{p=40+12   } 

\dashrightarrow\bold{P=52   } 

<u>So</u><u>,</u>

The value of <em>p</em><em> </em>is <em>5</em><em>2</em><em>.</em>

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A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)
Sliva [168]

"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.

well, we can check by simply getting the distance from the center to the point (4,-1).

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}

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3 years ago
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Bottom answer

Step-by-step explanation:

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have a good day :)

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HELP! I will mark branliest, please answer this question!!!<br><br> The value of x is ____?
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45x+angle trs = 180   straight line


angle trs = 180-45x


angle trs + angle t + angle tsr = 180  (sum of angles in a triangle =180)


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4 0
3 years ago
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